1.358 J is the kinetic energy of the car driven by Mrs. Waid.
<u>Explanation:</u>
Given data:
Velocity at which Mrs. Waid drives her car = 80 mph
In order to convert mph (meter per hour) into mps (meter per second),
Car weighs 2500 lbs, means mass of the car, m = 2500 lbs
I kilo gram = 2.20462 pound
Therefore, 1 pound (lb)= 0.45359237 kilograms (kg).
To converting pounds into kilogram,
As we know, the kinetic energy can be defined as directly proportionate to the object’s mass (m) and square of its velocity (v). The expression can be given as below,
By substituting the given values, we get
Answer:
18 m
Explanation:
E = mgh
45 J = (0.25 kg) (9.8 m/s²) h
h = 18 m
Answer:
Explanation:
For an electric force, F the formula:
F = kQq/r^2
Given:
r2 = 1/2 × r1
F1 × r1 = k
F1 × r1 = F2 × r2
F2 = (F1 × r1^2)/(0.5 × r1)^2
= (F1 × r1^2)/0.25r1^2
= 4 × F1.
The answer in this question is 44.7533 mphGiven information which we denote I as the distance of the automobile between the farmhouse, and S = the distance past the intersection of the highway and the road.
Then I^2 = 5^2 + s^2. Taking the derivative of both sides of this equation yields 2I(ds/dt) = 2s(ds/dt), so (dl/dt) = s(ds)/I(dt). When the automobile is 7 miles past the intersection we have;dl/dt = 55√(7/5^2 +7^2) and gives us the answer of approximately 44.7533 mph
Answer:
V = 1.1 m/s
Explanation:
given,
mass of railroad car 1 , m = 30,000. kg
travelling at the speed , u = 2.2 m/s
mass of car 2, M = 30,000. kg
initial speed, u' = 0 m/s
final speed of the car after collision, V = ?
using conservation of momentum
m u + M u' = (M+m)V
30000 x 2.2 + 0 = (30000 + 30000) V
60000 V = 66000
V = 1.1 m/s
he velocity of the two cars is equal to V = 1.1 m/s
