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Juli2301 [7.4K]
3 years ago
14

If you removed enough heat from water will it change into

Physics
1 answer:
stira [4]3 years ago
4 0
Answer is
Warm water
You might be interested in
Examine the scenario.
vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

velocity: 5 km/h north

is wrong, because the car is moving south, not north.

So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

v = 40 km/h is the final velocity

u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

And since the sign is positive, the direction is the same as the velocity (south).

7 0
3 years ago
The pictures below show a bottle made of plastic and a block made of concrete.
blsea [12.9K]
<span>Mineral is an inorganic solid, characterized with a definite chemical composition and ordered internal structure.</span>
Both plastic and concrete are not minerals because they are made by humans. They are not naturally occurring materials, which the minerals are.  
5 0
3 years ago
Read 2 more answers
What is the acceleration of a 600,000 kg freight train, if each of itsthree engines can provide 100,000 n of force?
sergey [27]

The acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a freight train can be calculated using the following formula:

Force = mass × acceleration

According to this question, a 600,000kg freight train can produce 100,000N of force. The acceleration is as follows:

100,000 = 600,000 × a

100,000 = 600,000a

a = 0.167m/s²

Therefore, the acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

Learn more about acceleration at: brainly.com/question/12550364

#SPJ1

6 0
2 years ago
When a gas is heated, it absorbs 196 joules of heat from the surroundings. At the same time, the gas expands, doing pressure-vol
timurjin [86]

Answer:

(a) q positive; w negative.

(b) ΔE = -126 J

(c) E and ΔE

Explanation:

<em>(a) Determine whether the amounts of heat (q) and work (w) exchanged should have positive or negative signs. heat (q) positive negative work (w) positive negative</em>

By convention, when the system absorbs heat from the surroundings, its sign is positive, that is, q = 196 J.

By convention, when the system exerts work on the surroundings, its sign is negative, that is, w = -322 J.

<em>(b) Calculate the change in internal energy (ΔE) of the gas. J</em>

The change in internal energy (ΔE) can be calculated using the following expression.

ΔE = q + w

ΔE = 196 J + (-322 J) = -126 J

<em>(c) Determine whether one or more of the following is a state function: </em>

<em> internal energy (E) of a system, </em>

<em>change in internal energy (ΔE) of a system, </em>

<em>heat (q) absorbed or released by a system, </em>

<em>work (w) done on or by a system.</em>

<em />

E and ΔE are state functions (they only depend on the states of the gas), whereas q and w depend on the trajectory.

7 0
3 years ago
The only force acting on a 3.1 kg body as it moves along the positive x axis has an x component fx = -8x n, where x is in meters
My name is Ann [436]
<span>(a) -9.97 m/s
 (b) x = 2.83

   This is a simple problem in integral calculus. You've been given part of the 2nd derivative (acceleration), but not quite. You've been given the force instead. So let's setup a function for acceleration.

   f''(x) = -8x N / 3.1 kg= -8x kg*m/s^2 / 3.1 kg = -2.580645161x m/s^2

   So the acceleration of the body is now expressed as
 f''(x) = -2.580645161x m/s^2

    Let's calculate the anti-derivative from that.
 f''(x) = -2.580645161x m/s^2
 f'(x) = -1.290322581x^2 + C m/s

   Now let's use the known velocity value at x = 2.0 to calculate C
 f'(x) = -1.290322581x^2 + C 1
1 = -1.290322581*2^2 + C
 11 = -1.290322581*4 + C
 11 = -5.161290323 + C
 16.161290323 = C

   So the velocity function is
  f'(x) = -1.290322581x^2 + 16.161290323

   (a) The velocity at x = 4.5
  f'(x) = -1.290322581x^2 + 16.161290323
 f'(4.5) = -1.290322581*4.5^2 + 16.161290323
 f'(4.5) = -1.290322581*20.25 + 16.161290323
  f'(4.5) = -26.12903227 + 16.161290323
 f'(4.5) = -9.967741942

   So the velocity is -9.97 m/s

   (b) we want a velocity of 5.8 m/s
5.8 = -1.290322581x^2 + 16.161290323
 0 = -1.290322581x^2 + 10.36129032
 1.290322581x^2 = 10.36129032
 x^2 = 8.029999998
 x = 2.833725463</span>
4 0
3 years ago
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