3 years ago

CJ = 82 + 5, CT = 55, and JT = 40 +2, Find JᎢ . The answer is JT:18

Chemistry

1 answer:

LenKa [72]3 years ago

7 0

Hehsnnsnsnsnanz shhshjzjjzja z

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What is the correct electron configuration of the element with atomic number 20?

IgorLugansk [536]

Answer:

D is the correct answer

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3 years ago

Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.

tamaranim1 [39]

Answer:

1500kg/m^3

Explanation:

Formula:

d=m/v

Given:

m=1.5kg

v=1000cm^3

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Required:

d=?

Solution:

d=m/v

d=1.5kg/1000cm^3

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Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.

Lady bird [3.3K]

Answer:

5.90, 11.8, 47.2

Explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴ $\text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{5.90 mol Mg atoms}$

$\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{11.8 mol Cl atoms}$

$\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{47.2 mol O atoms}$

∴ Mg, Cl, O = 5.90, 11.8, 47.2

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3 years ago

Please help me ASAP I’ll mark Brainly

mixer [17]

Answer:

cell

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3 years ago