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Crazy boy [7]
2 years ago
6

Why do paradigms change over time

Physics
1 answer:
Marina86 [1]2 years ago
8 0
Paradigms is a pattern or a model. They shift as a change in a way of thinking to another conclusion. After an amount of time they switch/shift into another pattern/position. 
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Each vertical line on the graph is 1 millisecond (0.001 s) of time. What is the period and
Mekhanik [1.2K]

Explanation:

Given that,

Each vertical line on the graph is 1 millisecond (0.001 s) of time.

We need to find the period and the frequency of the sound wave. The period of a wave is equal to the each vertical line on graph i.e. 0.001 s.

Let f be the frequency of the sound wave. So,

f = 1/T

i.e.

f=\dfrac{1}{0.001 }\\\\f=1000\ Hz

So, the period and the frequency of the sound waves is 1 milliseond and 1000 Hz respectively.

6 0
2 years ago
A man pushes a 60.8 kg crate across a rough surface with an applied force of 125 N and at a CONSTANT SPEED.
Sedbober [7]

Answer: Colby we both dumb if we need brainly lol

Explanation:

8 0
3 years ago
Simplify 6.25 − 8.<br><br>please help
tatyana61 [14]

6.25 - 8 = -1.75

Hope this helps

-AaronWiseIsBae

7 0
2 years ago
We have two solenoids: solenoid 2 has twice the diameter, half the length, and twice as many turns as solenoid 1. The current in
leva [86]

Answer:

the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.

Explanation:

Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:

B=\mu_0\, \frac{N}{L} I

Then, if we assign the subindex "1" to the quantities that define the magnetic field (B_1) inside solenoid 1, we have:

B_1=\mu_0\, \frac{N_1}{L_1} I_1

notice that there is no dependence on the diameter of the solenoid for this formula.

Now, if we write a similar formula for solenoid 2, given that it has :

1) half the length of solenoid 1 . Then L_2=L_1/2

2) twice as many turns as solenoid 1. Then N_2=2\,N_1

3) three times the current of solenoid 1. Then I_2=3\,I_1

we obtain:

B_2=\mu_0\, \frac{N_2}{L_2} I_2\\B_2=\mu_0\, \frac{2\,N_1}{L_1/2} 3\,I_1\\B_2=\mu_0\, 12\,\frac{N_1}{L_1} I_1\\B_2=12\,B_1

5 0
3 years ago
The diagram shows a screwdriver being used as a lever to open a tin
Musya8 [376]

Answer:

(a) Most reactive {}       Metal B

{}                                    Metal D

{}                                    Metal A

Least reactive {}           Metal C

(b) (i) Bubbles should form very slowly

(ii) No reaction takes place

Explanation:

(a) The given metals arranged in their order of reactivity are;

Most reactive {}       Metal B

{}                               Metal D

{}                               Metal A

Least reactive {}      Metal C

The other of reactivity is based on the nature of their reactivity of the metals in air

(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly

(ii) Similarly, given that metal C is unreactive, we have that when small pieces of metal C are added to dilute hydrochloric acid, no reaction takes place.

7 0
2 years ago
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