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3 years ago

Define temperature using molecular theory

2 answers:

6 0

Clearly, temperature has to do with the kinetic energy of the molecules, and if the molecules act like independent point masses, then we could define temperature in terms of the average translational kinetic energy of the molecules, the so-called "kinetic temperature".

Kitty [74]3 years ago

3 0

Answer: At the molecular level, temperature is related to the random motions of the particles (atoms and molecules) in matter. ... The temperature of the puddle, or of any object, is a measure of the average of the individual translational energies of all of its atoms or molecules.

Explanation: my science teacher already tought us this

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compare the distance time graph for a fast-moving object with the distance time graph of a slower moving object

soldi70 [24.7K]

The slope of the distance/time graph is the speed of the moving object.
So the graph for a fast moving object will have a greater slope than the
graph for a slower moving object has.

8 0

4 years ago

Why is there no drag in space?????? Help me please!!! Thanks!!!

astraxan [27]

It is beacuse of fluid If there is no fluid, there is no drag. Drag is generated by the difference in velocity between the solid object and the fluid. If this statement is correct then how can there be drag in space if there is no air?

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4 years ago

Read 2 more answers

A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the hori

lubasha [3.4K]

Answer:

$K.E = 163 J$

Explanation:

From the question we are told that:

Mass $m=4.1kg$

Height $h=4m$

Speed $V=1m/s$

Angle $\theta= 2 \textdegree$

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

$K.E=mgH + 0.5mV^2$

$K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5$

$K.E = 163 J$

6 0

3 years ago

A 4.0-ω resistor, an 8.0-ω resistor, and a 10.0-ω resistor are connected in series across an 11-V battery. The total potential d

Anon25 [30]

Total potential difference is 6

6 0

3 years ago

If the pipe of the previous exercise is connected to a hose and the speed there is 3.8 m/s, what is the diameter of the hose?

Amiraneli [1.4K]

The diameter of the hose is 6.34 cm.

"Your question is not complete, it seems to be missing the following information";

the flow rate of water in the pipe is 0.012 m³/s

The given parameters;

velocity of water in the hose, v = 3.8 m/s

flow rate of water in the hose, Q = 0.012 m³/s

Volumetric flow rate is directly proportional to the product of the area of the hose through which the water flows and the velocity of the water flowing through the hose.

Q = Av

where;

Q is the volumetric flow rate

A is the area of the hose

v is the velocity of flow

The area of the hose is calculated as follow;

$A = \frac{Q}{v} \\\\A = \frac{0.012}{3.8} \\\\A = 0.00316 \ m^2$

The diameter of the hose is calculated as follows;

$A = \frac{\pi D^2}{4} \\\\\pi D^2 = 4A\\\\D^2 = \frac{4 \times A}{\pi} \\\\D = \sqrt{\frac{4 \times A}{\pi} } \\\\D = \sqrt{\frac{4 \times 0.00316}{\pi} } \\\\D = 0.0634 \ m\\\\D = 6.34 \ cm$

Thus, the diameter of the hose is 6.34 cm.

Learn more here: brainly.com/question/15061170

4 0

2 years ago