Question

a solution is produced that contains 2.00 moles of sucrose dissolved in 1.00 L of water as the solvent. What is the MOLALITY of the solution

Answer 1

Answer:

$\boxed{\text{2.00 mol/L}}$

Explanation:

$\begin{array}{rcl}b& = &\dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\& = & \dfrac{\text{2.00 mol}}{\text{1.00 kg}}\\\\& = &\textbf{2.00 mol/kg}\\\end{array}\\\text{The molal concentration of the solution is \boxed{\textbf{2.00 mol/kg}} }$