None of the given options is correct based on the relationship for the components of the crate's weight.
The given parameter:
- <em>Angle of inclination, = q</em>
The vertical component of the force on the crate is calculated as follows;
The horizontal component of the crate is calculated as follows;
Thus, we can conclude that none of the given options is correct based on the relationship for the components of the crate's weight.
Learn more about forces on inclined weight here: brainly.com/question/11351170
Answer:
The answer is 271.3 joules .
Explanation:
Work = (weight) x (distance)
Work = (50 lb) x (1 kg / 2.20462 lb) x (9.81 newton/kg)
x (4 feet) x (1 meter / 3.28084 feet)
= (50 x 9.81 x 4) / (2.20462 x 3.28084) newton-meter
= 271.3 joules .
We don't need to know how long the lift took, unless we
want to know how much power he was able to deliver.
Power = (work) / (time)
= (271.3 joule) / (5 sec) = 54.3 watts .
________________________________________
The easy way:
Work = (weight) x (distance)
= (50 pounds) x (4 feet) = 200 foot-pounds
Look up (online) how many joules there are in 1 foot-pound.
There are 1.356 joules in 1 foot-pound.
So 200 foot-pounds = (200 x 1.356) = 271.2 joules.
credits original answer AL2006
V=IR
60-V
The current that passes through a 10-ohm resistor = I
I=60/10
6 amperes
Answer:
Explanation:
Firstly finding
So,
Substitute
Exchange the values of x and y
Solving for y
Adding 5 to both sides
Dividing both sides by 10
Replace
For x = -4
The airplane engine uses oxygen from the air to keep the engines working. Rockets must carry their oxygen for the engines to operate. Third Law of Motion). Rocket propellants by combustion provide the hot gas es that produce reaction force (thrust) when ejected to the rear.