Answer:
C
Explanation:
It is the answer I think let me know
Answer:
The acceleration of the bag of sand is 
.
Explanation:
We have,
Mass of a bag of sand is 100 kg
Weight of the bag of sand is 100 N
It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :
When it is dropped, a = g
So, the acceleration of the bag of sand is .
Answer:
Explanation:
Let v be the velocity acquired by electron in electric field
V q = 1/2 m v²
V is potential difference applied on charge q , m is mass of charge , v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron
= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
The horizontal velocity was constant, so:
it traveled 90meters
