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Lilit [14]
3 years ago
13

Which of these equations will you used to find the final velocity if the initial

Physics
1 answer:
Svetach [21]3 years ago
5 0

Answer:

2.77 would be the answer for this

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Mary wishes to lose 5 pounds before her vacation in approximately 5 weeks. Her average consumption is 2,100 kilocalories per day
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1,600 to 1,700 kilocalories per day

Explanation:

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What are three effect of force​
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1. Can change the state of an object(rest to motion/ motion to rest)

2. May change the speed of an object if it is already moving.

3. May change the direction of motion of an object.

Explanation: A force acting on an object causes the object to change its shape or size, to start moving, to stop moving, to accelerate or decelerate.

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A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?
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How do human break N2 into a useable form
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6 0
3 years ago
The World-War II battleship U.S.S Massachusetts used 16-inch guns whose barrel lengths were 15 m long. The shells each of mass 1
Vaselesa [24]

Answer:

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

Explanation:

Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:

F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2}) (1)

Where:

F - Explosive force, measured in newtons.

\Delta s - Barrel length, measured in meters.

m - Mass of the shell, measured in kilograms.

v_{o}, v_{f} - Initial and final speeds of the shell, measured in meters per second.

If we know that m = 1250\,kg, v_{o} = 0\,\frac{m}{s}, v_{f} = 750\,\frac{m}{s} and \Delta s = 15\,m, then the explosive force experienced by the shell inside the barrel is:

F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}

F = \frac{(1250\,kg)\cdot \left[\left(750\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (15\,m)}

F = 23437500\,N

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

6 0
3 years ago
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