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Lilit [14]
3 years ago
13

Which of these equations will you used to find the final velocity if the initial

Physics
1 answer:
Svetach [21]3 years ago
5 0

Answer:

2.77 would be the answer for this

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An electron and a proton are confined in the same space. For what particle would a measurement of the speed have a greater uncer
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3 0
3 years ago
This object has a mass of 45 kilograms. The applied force is 300 N and the force of friction is 120 N. What is the acceleration
yuradex [85]

Answer:

4ms^-2

Explanation:

m = 45Kg, Frictional force = 120N, Applied force = 300N, a = ?

Firstly, you find the net force acting on the body

Net force = Applied force - Frictional force

Net force = 300N - 120N = 180N

F = 180N

using the formula for Force

F = ma

Then making acceleration subject of the formula; you will get:

a = F/m

a = 180N/45Kg

a = 4ms^-2

3 0
3 years ago
One airplane is approaching an airport from the north at 181 kn/hr. A second airplane approaches from the east at 278 km/hr. Fin
umka2103 [35]

Answer:

The value  is  \frac{dR}{dt} =  -286.2 \  km/hr

Explanation:

From the question we are told that  

   The speed of the airplane from the north is \frac{dN}{dt}  =  -181 \  km /hr

The negative sign is because the direction is towards the south

  The speed of the airplane from the east is  \frac{dE}{dt}  =  -278 \  km/hr

The negative sign is because the direction is towards the west

   The distance of the southbound plane from the airport is  N  =  30 \  km

   The distance of the westbound plane is  E =  15 \  km

Generally the distance between the plane is mathematically represented using Pythagoras theorem  as

    R^2  = N^2 + E^2

Next differentiate implicitly this equation to obtain the rate at which the distance between the planes changes

So

     2R\frac{dR}{dt} =  2N \frac{dN}{dt} +   2E\frac{dE}{dt}

Here

     R = \sqrt{N^2 + E^2}

=>    R = \sqrt{30^2 + 15^2}

=>    R = \sqrt{30^2 + 15^2}

=>    R =33.54 \ m

    2(33.54) * \frac{dR}{dt} =  2( 30)*(-181)  +   2*15*(-278)

=>   67.08 * \frac{dR}{dt} =  -19200

=>   \frac{dR}{dt} =  -286.2 \  km/hr

4 0
4 years ago
Watts are measured in ____.
Lera25 [3.4K]
Here's a bad joke that helped me remember it: Watt's a Joule per second?
 
7 0
3 years ago
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