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ella [17]
3 years ago
10

A student constructs a galvanic cell that has a strip of iron metal immersed in a solution of 0.1M Fe(NO3)2 as one half-cell and

a strip of aluminum metal immersed in a solution of 0.1M Al(NO3)3 as the other half-cell. The measured cell potential is less than zero when the positive terminal of the voltmeter is attached to the aluminum strip and the negative terminal is attached to the iron strip. Which half-cell is the anode (Fe or Al)?
Chemistry
1 answer:
MrMuchimi3 years ago
4 0

Answer:

Fe

Explanation:

The cell potential is:

ΔE°cell = E°red(red) - E°red(oxid)

Where, E°red(red) is the reduction potential of the substance that is reducing, and E°red(oxid) is the reduction potential of the substance that is oxidizing. For the reaction be spontaneous and happen, ΔE°cell > 0.

The reduction takes place in the cathode, which is the negative pole, and the oxidation in the anode, which is the positive pole. So, the electrons flow from the positive pole to the negative pole (anode to cathode).

Then, if the voltmeter measured a negative potential, it means that is was attached incorrectly. So, the anode is Fe.

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A cube of an unknown metal is 1.25 inches on each side and has a mass of 128.3741 g. What is its' density?
Mademuasel [1]
Hey there!

To find the density of an object, you must use this formula:
Density=Mass/Volume

Knowing that your mass is 128.3741, the only information you need left would be to find the volume of the cube.

Because the side length of the cube is given, you can multiply the length three times in order to find its volume:
1.25*1.25*1.25
=1.953125

Now that you have your volume and mass, divide the mass by the volume to find the density:
128.3741/1.953125
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3 years ago
How can you tell one elements from another?
stepladder [879]
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What is the value of the activation energy of the uncatalyzed reaction?
Lubov Fominskaja [6]
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3 years ago
Given that kb for c6h5nh2 is 1.7 × 10-9 at 25 °c, what is the value of ka for c6h5nh3 at 25 °c?
lina2011 [118]

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To calculate the k_a of C_6H_5NH_3^+, we use the formula:

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Putting values in above equation, we get:

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3 years ago
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