1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara31 [8.8K]
3 years ago
12

What is Newton's Second Law of Motion? (2 points) Every reaction is equal to the force applied. Forces are balanced when they ar

e equal and opposite. The smaller the mass of an object, the greater the acceleration of that object when a force is applied. The greater the force applied, the greater the acceleration. An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force.
Physics
1 answer:
raketka [301]3 years ago
5 0

Well, they're not quite the way Newton expressed it, but out of all this mess of statements, there are two that are correct AND come from Newton's 2nd Law of Motion:

<em>-- The smaller the mass of an object, the greater the acceleration of that object when a force is applied. </em>

<em>-- The greater the force applied, the greater the acceleration.</em>

For the <u><em>other </em></u>statements in the question:

-- <em>Every reaction is equal to the force applied.</em>  True; comes from Newton's <u><em>3rd</em></u> law of motion.

-- <em>Forces are balanced when they are equal and opposite.</em>  True; kind of a definition, not from Newton's laws of motion.

-- <em>An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force. </em>  True; comes from Newton's <em><u>1st </u></em>law of motion.



You might be interested in
What is the formula for silver nitrate
serious [3.7K]

Answer:

Explanation:

Agno3

8 0
3 years ago
What causes an object to rotate
frez [133]
A spinning force acting upon it
3 0
3 years ago
Q 1 . How many significant figures are in the following measurement? 0.0009(1 point)
Crazy boy [7]

Here we have some questions about experimental errors.

Q1) We want to see how many significant figures have the measure:

0.0009

The number of significant figures is the number of known digits that are not the leading zeros.

Here we can see four leading zeros, and a single-digit different than zero, which is a 9.

Then we have only one significant figure, the 9.

Q2) Here we will use the measure that is the less exact, as the error of that measure may be larger than the smaller significant figures of the other measures.

Then:

31.2 lb + 38.02lb + 45 lb

The worst measure is 45lb, so the smallest significant figure that we should use is the first one at the left of the decimal point, then we need to round the other two measures to the next whole number, we will get:

31 lb + 38 lb + 45 lb = 114lbs

Q3) We know that the measure is 11.5 seconds and the uncertainty of 1.7%, then the uncertainty will be the 1.7% of the above measure:

(1.7%/100%)*11.5 s = 0.1955 s

Notice that our measure has one significant figure after the decimal point, so we need to round the error to the same significant figure.

0.1955 s ≈ 0.2s

Then the measure is:

11.5 s ± 0.20 s

Q4) We have the measure:

312.0 mph ± 3.9 mph.

The percent uncertainty will be the quotient between the error and the measure times 100%, or:

(3.9 mph/312.0 mph)*100%  = 1.25%

This is a percent error, we do not need to round this.

If you want to learn more, you can read:

brainly.com/question/17339020

5 0
2 years ago
A middle-A tuning fork vibrates with a frequency f of 440 hertz (cycles per second). You strike a middle-A tuning fork with a fo
jeyben [28]

Answer:

P = 5sin(880πt)

Explanation:

We write the pressure in the form P = Asin2πft where A = amplitude of pressure, f = frequency of vibration and t = time.

Now, striking the middle-A tuning fork with a force that produces a maximum pressure of 5 pascals implies A = 5 Pa.

Also, the frequency of vibration is 440 hertz. So, f = 440Hz

Thus, P = Asin2πft

P = 5sin2π(440)t

P = 5sin(880πt)

3 0
3 years ago
A violin with string length 32 cm and string density 1.5 g/cm resonates in its fundamental with the first overtone of a 2.0-m or
love history [14]

Answer:

T=1022.42 N

Explanation:

Given that

l = 32 cm ,μ = 1.5 g/cm

L =2 m  ,V= 344 m/s

The pipe is closed so n= 3 ,for first over tone

f=\dfrac{nV}{4L}

f=\dfrac{3\times 344}{4\times 2}

f= 129 Hz

The tension in the string given as

T = f²(4l²) μ

Now by putting the values

T = f²(4l²) μ

T = 129² x (4 x 0.32²)  x 1.5 x  10⁻³ x 100

T=1022.42 N

6 0
3 years ago
Other questions:
  • The voltage between the cathode and the screen of a television set is 22 kV. If we assume a speed of zero for an electron as it
    5·1 answer
  • An antitussive is a A. non-productive cough. B. cough-suppressant medication. C. cough medication used for drying up secretions.
    12·2 answers
  • According to Newton’s First Law of Motion, if a ball is rolled in a straight line in an open field, what will happen to the ball
    5·1 answer
  • a rock is dropped from a height of 80 m and is in free fall what is the velocity of as it reaches the ground 4.0 seconds later
    9·1 answer
  • Mercury is in the 80th position in the periodic table. How many protons does it have?
    11·2 answers
  • How can you double the frequency of a wave if you have control over both the wavelength and the wave velocity?
    5·2 answers
  • Select the correct answer.
    11·1 answer
  • Basketball is my favorite sport!
    6·2 answers
  • Begin any simulation, and turn on Gravity Force in the central menu on the right. The gravity force arrow shows the direction an
    12·1 answer
  • Consider the electric field lines shown in the diagram below. From the diagram, it is apparent that object A is ____ and object
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!