Part 1: Solve for the probability of Jerry owning an "on-time" bus
Of the 48 buses that run on time, Jerry owns 36 of them. Therefore, the probability of a bus running on time being owned by Jerry will be solved with the ratio of 36 buses to 48 buses.
This is represented by the fraction 36/48.
Simplifying this fraction will give us 3/4.
Convert to a decimal and then multiply by 100 to get a percentage - 75%.
Part 2: Solve for the probability of Jerry owning a "running late" bus
Of the 52 buses that run late, Jerry owns 7 of them. Therefore, the probability of a bus running late & being owned by Jerry will be solved with the ratio of 7 buses to 52 buses.
This is represented by the fraction 7/52.
Simplifying this fraction will give us 7/52 (cannot be simplified).
Convert to a decimal and then multiply by 100 to get a percentage - 13.46%.
