Answer:
0.42 m/s²
Explanation:
r = radius of the flywheel = 0.300 m
w₀ = initial angular speed = 0 rad/s
w = final angular speed = ?
θ = angular displacement = 60 deg = 1.05 rad
α = angular acceleration = 0.6 rad/s²
Using the equation
w² = w₀² + 2 α θ
w² = 0² + 2 (0.6) (1.05)
w = 1.12 rad/s
Tangential acceleration is given as
= r α = (0.300) (0.6) = 0.18 m/s²
Radial acceleration is given as
= r w² = (0.300) (1.12)² = 0.38 m/s²
Magnitude of resultant acceleration is given as
= 0.42 m/s²
Answer: Impulse = 20 Ns
Explanation:
Impulse is the product of force and time
Also impulse = momentum
Where momentum is the product of mass and velocity.
Given that
M = 2kg
V = 10 m/s
Impulse = MV = 2 × 10 = 20 Ns
Answer:
lift per meter of span = 702 N/m
Explanation:
See attached pictures.
Answer:
acceleration is the rate in which your speed increase at a constant or steady rate
Explanation:
The car’s momentum after 4.21s is 24617.4 kgm/s
<h3>
Newton's Second Law of Motion.</h3>
Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.
Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.
- Acceleration a = 2.45 m/s²
From Newton's second law,
F = (mv - mu) / t
ma = (mv - mu) / t
Substitute all the parameters into the formula above.
1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21
2940 = ( mv - 12240 ) / 4.21
Cross multiply
12377.4 = mv - 12240
Make mv the subject of the formula
mv = 12377.4 + 12240
mv = 24617.4 kgm/s
Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s
Learn more about Momentum here: brainly.com/question/25121535
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