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Shkiper50 [21]
4 years ago
13

Mechanical energy that has been "lost" to friction has actually been

Physics
2 answers:
umka21 [38]4 years ago
5 0
The answer to the question is true
Alex Ar [27]4 years ago
5 0

Answer:

it false, APEX, i just did this one

Explanation:

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There are 2 questions into 1
kiruha [24]

As we know that magnitude of the vector is 670 m

and it is inclined 25 degree with x axis

now we know that component of vector along x direction is given as

x = L cos\theta

x = 670 cos25

x = 610 m


Part 2)

In order to find the other component of the vector we can use

y = L sin\theta

y = 670 sin25

y = 280 m

3 0
4 years ago
I have completed 40 minutes of exercise today and will enter a short description in the course Activity Log. True or False
lesantik [10]
True if you actually did it. false if you didn't
8 0
3 years ago
A spherical balloon is made from a material whose mass is 3.00 kg. The thickness of the material is negligible compared to the 1
vesna_86 [32]

To solve the problem it is necessary to apply the definition of Newton's second Law and the definition of density.

Density means the relationship between volume and mass:

\rho = \frac{m}{V}

While Newton's second law expresses that force is given by

F = ma

Where,

m = mass

a= acceleration (gravity at this case)

In the case of the given data we have to,

m_b = 3Kg

r = 1.5m\\V = \frac{4}{3}\pi r^3 \\V = \frac{4}{3} \pi 1.5^3\\V = 14.13m^3

In equilibrium, the entire system is equal to zero, therefore

\sum F = 0

F_g +F_h-F_b = 0

Where,

F_g = Weight of balloon

F_h = Weight of helium gas

F_b = Bouyant force

Then we have,

mg+V\rho g -V\rho_a g = 0

\rho = \rho_0-\frac{m}{V}

Replacing the values we have that

\rho = 1.19kg/m^3 -\frac{3Kg}{14.13m^3}

\rho = 0.978kg/m^3

Now by ideal gas law we have that

PV=nRT

P\frac{\rho}{m} = nRT

P = \rho \frac{n}{m}RT

But the relation \frac{n}{m} is equal to the inverse of molar mass, that is

P = \frac{\rho}{M_0} RT

P = \frac{0.978kg/m^3}{0.04kg/mol}*8.314J/K.Mol * 305K

P = 619995.7Pa

Therefore the pressure of the helium gas assuming it is ideal is 0.61Mpa

5 0
3 years ago
In a process called pair production, an energetic
vredina [299]

Answer:

(3) mass-energy must be conserved

Explanation:

As we know that gamma rays are mass less and charge less photons which will have sufficient energy.

Now in case of Pair production the gamma photons convert its whole energy into  mass by the law of Einstein's mass energy equivalence relation.

As per his relation we can say

E = \Delta m c^2

here we will have

[tex]\Delta m[\tex] = mass produced

now we also have to think that here the two particles must have a pair of particles and antiparticles so that the combined mass system will have energy equivalent to the energy of gamma photons and also it must follow the conservation of charge

So here it will form an electron and a positron such that total charge will be zero and the energy will be same as energy of gamma photon.

3 0
4 years ago
Read 2 more answers
The instant before a tennis racquet hits a 0.057 kg tennis ball, the velocity of the ball is 55 m/s west. The instant after
Wewaii [24]

Answer: 6700m/s^2 E

Explanation:

Given the following :

Velocity of ball before being hit by a racquet = initial velocity(u) = 55m/s W

Velocity of the ball after being hit = final Velocity (v) = 45m/s E

Time of contact between ball and racquet (t) = 1.5 × 10^-2

The acceleration of a body is the change in Velocity of a body with time. It given by:

Acceleration (a) = [final Velocity(v) - initial velocity(u)] / time(t)

The westward direction is towards the left and thus Velocity takes a negative value, similarly, if it's towards the right, Velocity takes a positive value.

Therefore,

a = [45 - (-55)] / 1.5×10^-2

a = [45 + 55] / 0.015

a = 100 / 0.015

a = 6666.6666 m/s^2

a = 6700m/s^2 E

Since the value of acceleration is positive, the direction is towards the East (acceleration is in the direction of the ball's final Velocity).

5 0
3 years ago
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