We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL
c2 = 0.0313 M
concentration of diluted solution is 0.0313 M
Answer:
0.89
Explanation:
You are mixing an acid and a base, so there will be a neutralization reaction.
One of the reactants will be in excess, so we must determine its concentration and then calculate the pH.
<em>Moles of NaOH
</em>
Moles of NaOH = 25 × 0.173
Moles of NaOH = 4.32 mmol
===============
<em>Moles of HCl
</em>
Moles of HCl = 35 × 0.342
Moles of HCl = 12.0 mmol
===============
<em>Amount of excess reactant
</em>
NaOH + HCl ⟶ NaCl +H₂O
<em>n</em>/mmol: 4.32 12.0
The 4.32 mmol of NaOH reacts completely with 4.32 mmol of HCl.
Excess HCl = 12.0 – 4.32
Excess HCl = 7.6 mmol
===============
<em>Concentration of the excess HCl
</em>
Total volume = 25 + 35
Total volume = 60 mL
<em>c </em>= millimoles HCl/millilitres HCl
<em>c</em> = 7.6/60
<em>c</em> = 0.13 mol/L
===============
<em>Calculate the pH
</em>
The HCl dissociates completely to hydronium ions, so
[H₃O⁺] = 0.13 mol·L⁻¹
pH = -log[H₃O⁺]
pH = -log0.13
pH = 0.89
Answer:
the direct transfer of bacteria,viruses or other germs for one person to another.
Explanation:
sometimes this happens an individual with the bacterium or virus touches.kisses.or cough or sneeze on someone who isn't infected
