1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NeX [460]
3 years ago
8

Why is it important to know the accuracy and precision of a measuring device? Do you think that the dial caliper manufacturer’s

claim that the ""accuracy"" of the instrument is ±.001 is appropriate? Why or why not? Do you think that either of the dial calipers needs to be adjusted to accurately display measurements? Explain.
Engineering
1 answer:
Leto [7]3 years ago
3 0

Answer:

Accuracy and precision allow us to know how much we can rely on a measuring device readings. ±.001 as a "accuracy" claim is vague because there is no unit next to the figure and the claim fits better to the definition of precision.

Explanation:

Accuracy and Precision: the golden couple.

Accuracy and precision are key elements to define if a measuring device is reliable or not for a specific task. Accuracy determines how close are the readings from the ideal/calculated values. On the other hand, precision refers to repeatability, that is to say how constant the readings of a device are when measuring the same element at different times. One of those two key concepts may not fulfill the criteria for measuring tool to be used on certain engineering projects where lack of accuracy (disntant values from real ones) or precision (not constant readings) may lead to malfunctons and severe delays on the project development.

±.001 what unit?

The manufacturer says that is an accuracy indicator, nevertheless there is now unit stated so this is not useful to see how accurate the device is. Additionally, That notation is more used to refer to device tolerances, that is to say the range of possible values the instrument may show when reading and element. It means it tells us more about the device precision during measurments than actual accuracy. I would recommend the following to the dial calipers manufacturers to better explain its measurement specifications:

  1. Use  ±.001 as  a reference for precision. It is important to add the respective unit for that figure.
  2. Condcut test to define the actual accuracy value an present it using one of the common used units for that:  Error percentage or ppm.

You might be interested in
A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
creativ13 [48]

Answer:

6.5 × 10¹⁵/ cm³

Explanation:

Thinking process:

The relation N_{o} = N_{i} * \frac{E_{f}-E_{i}  }{KT}

With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹

and ni = 1.5 × 10¹⁰

Temperature, T = 300 K

K = 1.38 × 10⁻²³

This generates N₀ = 1.654 × 10¹⁶ per cube

Now, there are 10¹⁶ per cubic centimeter

Hence, N_{d}  = 1.65*10^{16}  - 10^{16} \\           = 6.5 * 10^{15} per cm cube

5 0
3 years ago
Read 2 more answers
Technician A says that a voltage drop of 0.8 volts on the starter ground circuit is within specifications. Technician B says tha
Romashka-Z-Leto [24]

Answer:

Technician A is wrong

Technician B is right

Explanation:

voltage drop of 0.8 volts on the starter ground circuit is not within specifications. Voltage drop should be within the range of 0.2 V to 0.6 V but not more than that.

A spun bearing can seize itself around the crankshaft journal causing it not to move. As the car ignition system is turned on, the stater may draw high current in order to counter this seizure.

8 0
3 years ago
Adam has 5 barrels of different volumes. The barrel of which volume can contain the most liquid?
Natalija [7]

Answer:

D

Explanation:

5 0
2 years ago
The heat required to raise the temperature of m (kg) of a liquid from T1 to T2 at constant pressure is Z T2CpT dT (1) In high sc
a_sh-v [17]

Answer:

(a)

<em>d</em>Q = m<em>d</em>q

<em>d</em>q = C_p<em>d</em>T

q = \int\limits^{T_2}_{T_1} {C_p} \, dT   = C_p (T₂ - T₁)

From the above equations, the underlying assumption is that  C_p remains constant with change in temperature.

(b)

Given;

V = 2L

T₁ = 300 K

Q₁ = 16.73 KJ    ,   Q₂ = 6.14 KJ

ΔT = 3.10 K       ,   ΔT₂ = 3.10 K  for calorimeter

Let C_{cal} be heat constant of calorimeter

Q₂ = C_{cal} ΔT

Heat absorbed by n-C₆H₁₄ = Q₁ - Q₂

Q₁ - Q₂ = m C_p ΔT

number of moles of n-C₆H₁₄, n = m/M

ρ = 650 kg/m³  at 300 K

M = 86.178 g/mol

m = ρv = 650 (2x10⁻³) = 1.3 kg

n = m/M => 1.3 / 0.086178 = 15.085 moles

Q₁ - Q₂ = m C_p' ΔT

C_p = (16.73 - 6.14) / (15.085 x 3.10)

C_p = 0.22646 KJ mol⁻¹ k⁻¹

6 0
3 years ago
To analyze and design a passive, first-order high-pass filter using a series RC circuit. An instrument needs to detect periodic
olga nikolaevna [1]

Answer:

R= 53.7 Ω

Explanation:

fc= 1/(2πRC)

3000=1/(2π× 1 × 10^-6 × R)

R= 53.7 Ω

6 0
3 years ago
Other questions:
  • Millions of years ago, the Sierra Nevada region began to be uplifted along a crack in Earth's crust. The region on the other sid
    14·1 answer
  • Verify the below velocity distribution describes a fluid in a state of pure rotation. What is the angular Velocity? (a)-Vx = -1/
    7·1 answer
  • Lately, you have noticed some repetitive stress in your wrist. Which sign is most likely the cause of that stress and pain?
    7·1 answer
  • Give the approximate temperature at which creep deformation becomes an important consideration for each of the following metals:
    5·1 answer
  • An ideal Diesel cycle has a compression ratio of 17 and a cutoff ratio of 1.3. Determine the maximum temperature of the air and
    10·1 answer
  • What are two reasons why Hunter edjucation is important?<br><br><br> 30 pts
    12·1 answer
  • Which happens when a wave passes through an opening
    12·2 answers
  • ¿Cuál es el objetivo de la participación del gobierno en la economía?
    6·1 answer
  • Workers who work with what kind of chemicals chemicals may require regular medical checkups on a more frequent basis as a result
    15·1 answer
  • When bending metal, the material on the outside of the curve stretches while the material on the inside of the curve compresses.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!