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IceJOKER [234]
3 years ago
9

La extensión de un resumen debe estar en un rango de _________ del texto inicial. a)25 a 35 % b)10 a 20 % c)15 a 20 % d)20 a 25

%
Engineering
1 answer:
mestny [16]3 years ago
3 0

Answer:

b)

Explanation:

because it is correct

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Write a program in C++ that can be used by a small theater to sell tickets for performances.The theater’s auditorium has 15 rows
Natalka [10]

Answer:

See explaination

Explanation:

#include<iostream>

using namespace std;

char seating[15][20];

float row_price[15];

//This function will display the seating chart

void display()

{

cout<<"-------------------------- Seating Chart----------------------------\n";

cout<<"Seats: ";

for(int i=0;i<20;i++)

cout<<i<<" ";

cout<<"\n";

for(int i=0;i<15;i++)

{

if(i<10)

cout<<"Row "<<i<<" ";

else

cout<<"Row "<<i<<" ";

for(int j=0;j<20;j++)

{

if(j<10)

cout<<seating[i][j]<<" ";

else

cout<<seating[i][j]<<" ";

}

cout<<"\n";

}

}

//This function will prompt to the user to enter row fares

void row_price_details()

{

cout<<"Enter row wise fares:\n";

for(int i=0;i<15;i++)

cin>>row_price[i];

}

//Main function

int main()

{

char choice;

int i,j,row,seat;

float revenue=0;

//step-1 initializing seating chart with * (available)

for(i=0;i<15;i++)

{

for(j=0;j<20;j++)

{

seating[i][j]='*';

}

}

//displaying seating chart by calling display() function

display();

//prompt the user to enter row fares by calling row_price_details() function

row_price_details();

//Booking seats until user say n or N

do{

cout<<"Enter Row number and Seat number:\n";

cin>>row>>seat;//getting seat and row numbers

//validating enter seat number or row number or with in boundry or not

//if not displays Error message

if(row<15||seat<<20)

{

//checking entered position is available or not

//if not displays sorry message

if(seating[row][seat]=='*')

{

revenue=revenue+row_price[row];//calculating revenue

seating[row][seat]='#';//making seat unavailable

cout<<"Thankyou for Booking\n";

}

//sorry message

else

{

cout<<"The position yor entered is not available\n See seating chart to know available seats\n";

display();

}

}

//Error message

else

{

cout<<"Invalid seat number or row number....\n";

}

cout<<"Do you want to buy another ticket?\nif yes enter Y or y else N or n\n";

cin>>choice;

}while(choice=='Y'||choice=='y');

//displaying summery of the booking

//seating chart and revenue

cout<<"After booking the seating chart:\n";

display();

cout<<"Total Revenue:\n"<<revenue;

}

7 0
3 years ago
The components of an electronic system dissipating 180 W are located in a 1-m-long horizontal duct whose cross section is 16 cm
oee [108]

Answer:

a) The exit temperature is 39.25°C

b) The highest component surface is 132.22°C

c) The average temperature for air equal to 35°C is a good assumption because the air temperature at the inlet will increase due to the result in the heat gain produced by the duct and whose surface is exposed to a flow of hot.

Explanation:

a) The properties of the air at 35°C:

p = density = 1.145 kg/m³

v = 1.655x10⁻⁵m²/s

k = 0.02625 W/m°C

Pr = 0.7268

cp = 1007 J/kg°C

a) The mass flow rate of air is equal to:

m=\rho *V = 1.145*0.65=0.7443kg/min=0.0124kg/s

The exit temperature is:

T=T_{i} +\frac{Q}{m*c_{p} } =27+\frac{0.85*180}{0.0124*1007} =39.25°C

b) The mean fluid velocity is:

V_{m} =\frac{V}{A} =\frac{0.65}{0.16*0.16} =25.4m/min=0.4232m/s

The hydraulic diameter is:

D_{h} =\frac{4A}{p} =\frac{4*0.16*0.16}{4*0.16} =0.16m

The Reynold´s number is:

Re=\frac{VD_{h} }{v} =\frac{0.4232*0.16}{1.655x10^{-5} } =4091.36

Assuming fully developed turbulent flow, the Nusselt number is:

Nu=0.023Re^{0.8} *Pr^{0.4} =0.023*4091.36^{0.8} *0.7268^{0.4} =15.69

h=\frac{k*Nu}{D_{h} } =\frac{0.02625*15.69}{0.16} =2.57W/m^{2} C

The highest component surface temperature is:

T=T_{e} +\frac{\frac{Q}{A} }{h} =39.2+\frac{0.85*\frac{180}{4*0.16*1} }{2.57} =132.22°C

6 0
3 years ago
Products. of sheet metal​
Blababa [14]
Automobiles and Airplanes is what I can think of
3 0
3 years ago
Water is pumped from a lower reservoir to a higher reservoir by a pump that provides 20 kW of shaft power. The free surface of t
ahrayia [7]

Answer:

note:

<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>

8 0
3 years ago
Chapter 15 – Fasteners: Determine the tensile load capacity of a 5/16 – 18 UNC thread and a 5/16 – 24 UNF thread made of the sam
Roman55 [17]

Answer:

The 5/16 – 24 UNF is stronger because it has more tensile load capacity.

Tensile load capacity for M8 -1.25 = 5670 lb

Tensile load capacity for M8 -1 = 6067 lb

Explanation:

For 5/16 - 18 UNC thread:

D = 0.3125

n = 18

Therefore the tensile load capacity is = 100000 X (0.7854 X (0.3125 - 0.9743/ 18) ^2

= 5243 lb.

Similarly for 5/16 - 24 UNF , only the n value changes to 24

we get the tensile load capacity = 5806.6 lb

Hence the 5/16 – 24 UNF is stronger because it has more tensile load capacity.

For metric Bolts:

We have to consider all values in SI units

Strength = 689 MPa

We get for M8 -1.25:

Tensile load capacity as = 689 X 36.6 = 25223 N = 5670 lb

For M8 -1:

Tensile load capacity as = 689 X 39.167 = 26986 N = 6067lb

7 0
3 years ago
Read 2 more answers
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