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lisov135 [29]
3 years ago
15

Bridget is riding her bicycle up a hill. Which statements are correct? Select five options.

Physics
2 answers:
Flura [38]3 years ago
5 0

Answer:

A,B,C,D, and F are correct

Explanation:

Stels [109]3 years ago
5 0
I believe it’s because Bridget was transferring energy so B
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Waves transfer energy. What have you observed about light, sound, or water that could support this claim?
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Light warms objects when it shines on them. Sound waves from a powerful stereo can make the floor vibrate. Water waves crash on the beach with force. These observations support the claim that waves transfer energy.

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The ____________________ (Newton/Kelvin) is the SI unit for temperature.
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The si unit for temperature is Kelvin(k)
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4 years ago
A 9.800 mol sample of nitrogen gas is maintained in a 0.8166 L container at 301.8 K. What is the pressure in atm calculated usin
cluponka [151]

Answer:

P = 359.8 atm

Explanation:

The van der Waals' equation relates the properties of a gas, introducing constants "a" and "b" in order to consider gases as real gases. The equation is:

(P+a.\frac{n^{2} }{V^{2} } ).(V-nb)=n.R.T

where,

P: pressure

a: correction factor for intermolecular forces

V: volume

b: correction factor for molecules' volume

n: moles

R: ideal gas constant

T: absolute temperature

(P+\frac{1.390L^{2}atm}{mol^{2}}.\frac{(9.800mol)^{2}}{(0.8166L)^{2}}).(0.8166L-9.800mol.\frac{3.910 \times 10^{-2}L}{mol})=9.800mol \times \frac{0.08206atm.L}{mol.K} \times 301.8K\\(P + 200.2atm).(0.4334L) = 242.7atm.L\\P=359.8 atm

8 0
3 years ago
Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings
Hatshy [7]

Answer:0.316 rad/s

Explanation:

Given

mass of Person m=65 kg

velocity of person v=3.8 m/s

diameter of turntable d=6.5 m

moment of Inertia of the table I_0=1850 kg-m^2

Moment of inertia of Person I

I=mr^2=65\times (\frac{6.5}{2})^2

I=686.56 kg-m^2

initial angular velocity \omega _1=\frac{v}{r}

\omega _1=\frac{3.8}{3.25}=1.17 rad/s

Conserving Angular momentum

I\omega _1=(I+I_0)\omega _2 , where \omega _2=final\ angular\ velocity

686.56\times 1.17=(686.56+1850)\times \omega _2

\omega _2=\frac{686.56}{2536.56}\times 1.17

\omega _2=0.316 rad/s

4 0
3 years ago
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