Bode law, a planet<span> was believed to exist </span>between<span> .... An Astronomer's Account of the </span>Missing Planet Between<span> Mars and </span>Jupiter<span> as Interpreted </span>Jupiter<span> ·</span>Saturn<span> · Uranus · Neptune.</span>
Answer:
On a roller coaster, energy changes from potential to kinetic and back again many times over and over the course of the ride. Kinetic energy is energy that an object has because of its motion. All moving objects possess kinetic energy, which is determined by the mass and speed of the object.
Explanation:
Perimeter=26in
Area would be to multiply the units together
Answer:
Part A: 
Part B: 
Part C: 
Explanation:
Part A:
We will use the following kinematics equation:

Part B:
We will use the same kinematics equation:

Part C:
The total time takes is 2t.
So the train moves a distance of

And the car moves a distance in Part A and in Part B:

So the total distance that the car traveled is 
The difference between the train and the car is

Weight = (mass) x (gravity).
It always acts downward.
On Earth, the acceleration of gravity is 9.807 m/s².
On the Moon, the acceleration of gravity is 1.623 m/s².
On Earth, the rocket's weight is (0.8kg) x (9.8 m/s²) = 7.84 newtons
On the Moon, the rocket's weight is (0.8kg) x (1.62 m/s²) = 1.3 newtons
The force of the rocket engine acts upward.
Its magnitude is 12 newtons. (From the burning chemicals.
Doesn't depend on local gravity. Same force everywhere.)
Now we have all the data we need to mash together and calculate the
answers to the question. You might choose a different method, but the
machine that I have selected to do the mashing with is Newton's 2nd law
of motion:
Net Force = (mass) x (acceleration).
Since the question is asking for acceleration, let's first solve Newton's law
for it. Divide each side by (mass) and we have
Acceleration = (net force) / (mass) .
On Earth, the forces on the rocket are
(weight of 7.84 N down) + (blast of 12 N up) = 4.16 newtons UP (net)
Acceleration = (4.16 newtons UP) / (0.8 kg) = 5.2 m/s² UP .
On the moon, the forces on the rocket are
(weight of 1.3 N down) + (blast of 12 N up) = 10.7 newtons UP (net)
Acceleration = (10.7 newtons UP) / (0.8 kg) = 13.375 m/s² UP