acceleration of the car = 0.33 m/s²
Explanation:
To calculate the acceleration of the car we use the following formula:
acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
change in velocity = 23 m/s - 13 m/s = 10 m/s
change in velocity = 10 m/s
acceleration = 10 m/s / 30 s
acceleration = 0.33 m/s²
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acceleration
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The speed of the space craft relative to the earth is given as: 0.024c. This is solved using the the equation for time dilation.
<h3>
What is time dilation?</h3>
Time dilation is the "slowing down" of a clock as determined by an observer in relative motion with regard to that clock under the theory of special relativity.
The formula is given as :
Δt = [Δr]/ √ 1 - (v²/c²)
Thus,
v = c√1 - (Δr/Δt)²
= c √(1 - (3600/3601)²
v = 0.024c
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The correct answer is: C. It is the point beyond which neither light nor anything else can escape.
Answer:
135 N
Explanation:
Given that:
In a tug of war, team A pulls the rope with a force of 225 N; &
Team B also pulls with a force of 360 N
The magnitude of the resultant force is the difference between the two forces since they are positioned in the opposite direction.
Thus;
The magnitude = 360 N - 225 N
So, magnitude of resultant force on the rope = 135 N
The object rises to a height of 20.4 m. So option C is correct.
Explanation:
initial velocity= Vi=20 m/s
final velocity at the top= Vf=0
acceleration= g=-9.8 m/s²
Vf²=Vi²+2gh
0= (20)²+2 (-9.8)h
-200=-9.8h
h=200/9.8
h=20.4 m
Thus the object rises to a height of 20.4 m
