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3 years ago

Real life example for each gas law

1 answer:

3 0

Applications of Gas Law in Real Life. A torch used to heat up the and rise the air temperature inside the balloon. This cause the air volume inside the balloon to increased and becoming less dense than the surrounding air. ... The air in the ears will change its volume then causes yours ears to pop due to the strain.

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Once juno reaches jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft

Komok [63]

In very very very round figures . . .

-- Jupiter is about 5.2 times as far from the sun as the earth is.

-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about

(4.2) x (150 million kilometers) = 630 million kilometers

Time = (distance) / (speed)

The speed of light and radio is 300,000 km/second

Time = (630 million / 300 thousand)

<em>Time = 2,100 seconds</em>

That's 35 minutes.

4 0

3 years ago

Read 2 more answers

A guitar string vibrates 600 times in 2 seconds.

vazorg [7]

frequency is equal to number of oscillations or vibrations upon time

therefore,

check picture

4 0

2 years ago

A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What

icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, $F_f$ , acting in the opposite direction (backward)

So the net force acting on the box is

$F_{net}=F-F_f$

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

$F_{net}=ma$

And so

$F-F_f = ma$

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

$a=0$

Therefore we have:

$F-F_f=0$

Which means

$F_f=F$

And since we are told that

$F=25 N$

This means that the force of friction is also 25 N:

$F_f=F=25 N$

6 0

3 years ago

Read 2 more answers

A ball player catches a ball 3.2 s after throwing it vertically upward. what height did it reach?

cluponka [151]

At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e $-9.8 m/s^2$ ).

The time of the ball in air is 3.2 s, so ascending time is $3.2/2=1.6 s$ .

Therefore from kinematic equation,

$v = u + gt$

Substituting the values we get,

$0= u - 9.8 (1.6)\\\\u=15.7 m/s$ , Here v = 0 at top.

Now from equation,

$h=ut+\frac{1}{2} gt^2$ , here h is the height .

So,

$h=(15.7 m/s) (1.6s)-\frac{1}{2} 9.8m/s^2(1.6)^2\\\\ h=25.12m-12.54m\\\\h=12.48 m$ .

Thus, the ball reached at its maximum height of 12.48 m.

8 0

3 years ago

The horizontal motion of a launched projectile affects its vertical motion.

Talja [164]

The horizontal motion of a launched projectile affects its vertical motion is false

Answer: False

<u>Explanation: </u>

As the trajectory falls on a plane, all the components like displacement, velocity can be classified in two components termed as horizontal and vertical component.

In a projectile motion, the horizontal components of displacement and velocity remains constant and there is change only in the vertical component of displacement and velocity.

Both components are not dependent to each other. So, the horizontal motions of a launched projectile does not affect its vertical motion.

8 0

3 years ago