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PilotLPTM [1.2K]
4 years ago
6

Real life example for each gas law

Physics
1 answer:
Dvinal [7]4 years ago
3 0
Applications of Gas Law in Real Life. A torch used to heat up the and rise the air temperature inside the balloon. This cause the air volume inside the balloon to increased and becoming less dense than the surrounding air. ... The air in the ears will change its volume then causes yours ears to pop due to the strain.
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Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
krek1111 [17]

Answer:

Explanation:

The path length difference = extra distance traveled

The destructive interference condition is:

\Delta d = (m+1/2)\lambda

where m =0,1, 2,3........

So, ←

\Delta d = (m+1/2)\lamb da9/tex]so [tex]\Delta d = \frac{\lambda}{2}

⇒ λ = 2Δd = 2×10 = 20

4 0
3 years ago
on a high way a car is driven 80 km the first 1 he of travel, 50km during the next 0.5 he, and 40 km in the final 0.5 hr. What i
Leno4ka [110]

Average speed = (total distance covered) / (total time to cover the distance) .

Total distance = (80 + 50 + 40) = 170 km

Total time = (1 + 0.5 + 0.5) = 2 hours

Average speed = (170 km) / (2 hrs) = 85 km/hr .
 
4 0
3 years ago
The momentum of an object is proportional to its weight and speed.<br> a. true<br> b. false
Crank
It would be A.. True
4 0
4 years ago
A bullet is fired horizontally from a 17.7 m high cliff at a speed of 482.0. What is the distance from the cliff that the bullet
Marysya12 [62]

Answer:

Horizontal distance=?m

Explanation:

Horizontal velocity,u=482ms⁻¹

Height of the cliff=17.7m

Horizontal distance,R=?

R=v×√2h/g

5 0
3 years ago
The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. Th
jekas [21]

Answer:

The right solution is "126 Psi".

Explanation:

The given values are:

P₁ = 130 psig

i.e.,

   = 130\times 6.894

   = 896.22 \ Kpa

or,

   = 896.22\times 10^3 \ Pa

Z₂ = 10ft

    = 3.05 m

\delta = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒  \frac{P_1}{\delta_g} +\frac{V_1^2}{2g} +Z_1=\frac{P_2}{\delta_g} +\frac{V_2^2}{2g} +Z_2

On substituting the values, we get

⇒  \frac{P_1}{\delta_g} +0+0=\frac{P_2}{\delta_g} +0+Z_2

⇒  \frac{896.22\times 10^3}{1000\times 9.8} =\frac{P_2}{1000\times 9.8} +3.05

⇒  P_2=866330 \ P_a

i.e.,

⇒       =866330\times 0.000145

⇒       =126 \ Psi

8 0
3 years ago
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