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SashulF [63]
3 years ago
11

What is the slit spacing of a diffraction necessary for a 600 nm light to have a first order principal maximum at 25.0°?

Physics
1 answer:
Sauron [17]3 years ago
6 0

Explanation:

Given that,

Wavelength of light, \lambda=600\ nm=6\times 10^{-7}\ m

Angle, \theta=25^{\circ}

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

d\sin\theta=n\lambda

n is 1 here

d is slit spacing

d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m

So, the slit spacing is 1.41\ \mu m.

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