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iris [78.8K]
3 years ago
10

Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minu

te for the next 350 meters, and 3 minutes for the rest.
Cindy’s average speed for the entire run is
( )
meters per minute. One kilometer is the same as 1,000 meters.

Hint: distance over time
Chemistry
2 answers:
lubasha [3.4K]3 years ago
8 0
I can say that 200 m/m is correct on Edmentum/ Treca I got 5/5 on the test
Andrei [34K]3 years ago
7 0

In order to calculate average speed we will calculate the total distance in meters traveled by cindy.

Distance = 2 Km

1 km = 1000m

So distance in meters = 2000 m

Then let us calculate the total time taken by cindy to cover these 2000 meters

Total time in minutes = 2 + 4 + 1 + 3 = 10 minute

Average speed = total distance  / total time

Average speed = 2000 m / 10 minutes

average speed = 200 m / min

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The following Balanced Reaction will take place:

Zn + 2HCl → ZnCl₂ + H₂

In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction

<u>Amount of HCl required to completely react with 2 moles of Zn:</u>

Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn

<u>Identifying the Limiting Reagent:</u>

But we are only given 3 moles of HCl where we need 4 moles to completely react.

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8 0
2 years ago
Is apple juice a homogeneous mixture or a heterogeneous mixture
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5 0
3 years ago
Read 2 more answers
Someone help me pleasee?
Kamila [148]
Maybe its the second one
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3 years ago
Which sequence contains elements listed from most reactive<br> to least reactive?
maxonik [38]

Answer:

Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.

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6 0
3 years ago
What is the energy per mole of photons, in kJ/mol, emitted by an argon ion laser which produces a green beam with a frequency of
Serga [27]

Answer:

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