Question

How many joules are required to raise the temperature of a 6.50 g sample of silver from 34°c to 189°C? The specific heat of gold is 0.235j/g°c

Answer 1

Answer:

236.76 J

Explanation:

Parameters given:

Mass of sample, m = 6.50 g

Initial temperature, $T_1 = 34^o C$

Final temperature, $T_2 = 189^oC$

Specific heat capacity of gold, $c = 0.235 J/g^oC$

Heat of a substance is related to specific heat capacity by the formula:

$H = mc(T_2 - T_1)$

$H = 6.5 * 0.235 * (189 - 34)\\\\\\H = 6.5 * 0.235 * 155\\\\\\H = 236.76 J$

236.76 J of heat is required to raise the temperature of the sample.