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andreyandreev [35.5K]
2 years ago
7

What happens to oxygen and carbon dioxide in the respiratory system?

Chemistry
1 answer:
lara [203]2 years ago
8 0

Answer:

In the respiratory system, oxygen is breathed in and carbon dioxide ( a green house gas) is breathed out.

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FIST ONE TO AWNSER GETS BRAINLYIST AND 50 POINTS IF CORRECT HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
grin007 [14]

Answer:

B

Explanation:

Shows actual sacrifice in order to train and be the best.

7 0
3 years ago
Read 2 more answers
how many ml of a 22.5% (v/v) ethanol solution would you need to measure out in order to have 12.5 ml of ethanol ?
Aleks [24]
Volume percent<span> or </span>volume/volume percent<span> (v/v%) is used when preparing solutions of liquids. It will have units of volume of the smaller composition substance over the volume of the solution. We calculate as follows:

12.5 mL ethanol = .225 mL ethanol / 1 mL solution ( V )
V = 55.56 mL of the 22.5 % by volume ethanol solution is needed

Hope this answers the question.</span>
8 0
3 years ago
How many moles of solute particles are present in 1 ml of aqueous 0.020 m (nh4)2co3?
Dima020 [189]
Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?

For the purpose, here we will use the next equation:

c=n/V ⇒ n=cxV

n((NH4)2CO3) = 0.02M x 0.001L 

n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution


6 0
3 years ago
3<br> Convert 5.492 x 104 grams to units of micrograms.<br> (Click to select 4<br> x 10<br> ug
Soloha48 [4]

Answer:

5.492*10^10

Explanation:

1g=1000000microgram

3 0
2 years ago
8. A student filled a graduated cylinder with water and read the meniscus at 25.8 mL. The student
fomenos

Answer:

<h2>30.2 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

volume = final volume of water - initial volume of water

From the question

volume = 35.9 ml - 25.8 ml = 10.1 mL

We have

mass = 2.99 × 10.1 = 30.199 g

We have the final answer as

<h3>30.2 g</h3>

Hope this helps you

5 0
3 years ago
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