The height of the cliff will be 25.05 m. The height of the cliff is obtained by the Newton equation of motion.
<h3>What is height?</h3>
The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.
The given data in the problem is;
Mass of diver(m)=90 kilogram
Time period(t)=2.26 sec
Initial velocity (u)=0 m/sec
The height attained by the cliff is;
Hence, the height of the cliff will be 25.05 m.
To learn more about the height, refer to the link;
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Water pressure is greater at the bottom of the deep end of the pool when compares to the shallow end of the pool because all of the weight of the water is compressed and pushed down (there is more volume on the deep side).
Think of it like this:
You wear your hat - only 1. It's normal, you only feel the hat fit on. Now imagine that you wear about 10 hats, it starts to feel uncomfortable and after a while, your neck will get stiff due to the pressure of the hats pushing down on your spinal cord. Now imagine 100 hats - the deeper you go, the more pressure is forced on you.
The final velocity of the object is 16m\s.
Hope this helps! :)
A) Using:
2as = v² - u², where v will be 0 at max height
s = -(160)² / 2 x -32.174
s = 397.8 ft
b) Using:
s = ut + 1/2 at²
256 = 160t - 16.1t²
solving for t,
t = 2.0, t = 7.9
Now, v = u + at, for both times:
v(2) = 160 - 32.174(2)
v(2) = 95.7 ft/sec on the way up
v(7.9) = 160 - 32.174(7.9)
v(7.9) = -94.3 ft/sec; 94.3 ft/sec on the way down
c) -32.174 ft/s², which is the acceleration due to gravity.
d) s = 0
0 = 160t - 1/2 x 32.174t²
t = 9.94 seconds
K:potassium
Cu:copper
Cl: chlorine
