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sineoko [7]
3 years ago
13

A 35 grams bullet travels with a velocity of magnitude 126 km/h. What is the bullet's linear momentum?

Physics
1 answer:
LekaFEV [45]3 years ago
3 0

Answer:

IDK

Explanation:

idk

You might be interested in
3 points
Ilia_Sergeevich [38]

Answer:

Potential

Explanation:

The water in the bathtub has more potential energy than that in the tea cup because it has a greater number of water molecules.

Mass is a parameter that is very instrumental in determining potential energy.

The potential energy of a body is the energy due to the position of that body.

   Potential energy  = mass x acceleration due gravity x height

Mass is the amount of matter in a substance. Water in the tub will have more mass and contain a greater number of water molecules there in.

Since potential energy is directly proportional to mass, then, it will have a greater amount of potential energy.

3 0
2 years ago
A locomotive has a mass of 200,000kg. It is moving at 4.5m/s. Find its momentum .
anastassius [24]
Momentum (p) = mass × velocity

P= 200,000×4.5

P= 900,000 .... answer !!
4 0
3 years ago
Read 2 more answers
4.2 mol of monatomic gas A interacts with 3.2 mol of monatomic gas B. Gas A initially has 9500 J of thermal energy, but in the p
Komok [63]

Answer:

14657.32 J

Explanation:

Given Parameters ;

Number of moles mono atomic gas A ,   n 1  =  4 .2 mol

Number of moles mono atomic gas B ,   n 2  =  3.2mol

Initial energy of gas A ,   K A  =  9500  J

Thermal energy given by gas A to gas B ,   Δ K  =  600 J

Gas constant   R  = 8.314  J / molK

Let  K B  be the initial energy of gas B.

Let T be the equilibrium temperature of the gas after mixing.

Then we can write the energy of gas A after mixing as

(3/2)n1RT = KA - ΔK

⟹ (3/2) x 4.2 x 8.314 x T = 9500 - 600

T = (8900 x 3 )/(2x4.2x8.314) = 382.32 K

Energy of the gas B after mixing can be written as

(3/2)n2RT = KB + ΔK

⟹ (3/2) x 3.2 x 8.314 x 382.32 = KB + 600

⟹ KB = [(3/2) x 3.2 x 8.314 x 382.32] - 600

⟹ KB = 14657.32 J

6 0
3 years ago
Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
Oksanka [162]

Explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

v=\dfrac{c}{\mu}....(I)

Where, \mu = index of refraction

c = speed of light

Put the value into the formula

v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.63}

v=1.8\times10^{8}\ m/s

(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.50}

v=2\times10^{8}\ m/s

Hence, This is the required solution.

7 0
3 years ago
( timed for this!! please help!!) Which best defines scientific question?
Viefleur [7K]
My opinion, the answer is b

5 0
2 years ago
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