This question provides us –
- Weight of
is = 47 g - Volume, V = 375 mL
__________________________________________
- Molar Mass of
–
![\twoheadrightarrow\bf 39.0983 \times 35.453](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20%2039.0983%20%5Ctimes%2035.453%20)
![\twoheadrightarrow\bf 74.5513](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%2074.5513)
<u>Using formula</u> –
![\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W\times 1000}{MV}}](https://tex.z-dn.net/?f=%5Cpurple%7B%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%3D%20%20%5Cdfrac%7B%20W%5Ctimes%201000%7D%7BMV%7D%7D)
![\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 47 \times 1000}{74.5513\times 375}](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%20%3D%20%5Cdfrac%7B%2047%20%5Ctimes%201000%7D%7B74.5513%5Ctimes%20375%7D)
![\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{47000}{27956.7375}](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%20%3D%20%5Cdfrac%7B47000%7D%7B27956.7375%7D)
![\twoheadrightarrow\bf Molarity _{(Solution)} = \cancel{\dfrac{47000}{27956.7375}}](https://tex.z-dn.net/?f=%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%20%3D%20%5Ccancel%7B%5Cdfrac%7B47000%7D%7B27956.7375%7D%7D)
![\twoheadrightarrow\bf Molarity _{(Solution)} = 1.68117M](https://tex.z-dn.net/?f=%20%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%20%3D%201.68117M%20)
![\pink{\twoheadrightarrow\bf Molarity _{(Solution)} = 1.7M}](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%5Cbf%20Molarity%20_%7B%28Solution%29%7D%20%20%3D%201.7M%7D%20)
- Henceforth, Molarity of the solution is = 1.7M
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Answer:
Mass=50.0g
H=670J
change in temperature=40
using. c=h÷m×change in temperature
c=670÷50×40
C=670÷2000
C=0.335jkg-1k-1
Answer:
a small unit of measurement used for measuring data is bit.
Answer:
49.14 carat.
Explanation:
From the question given above, we obtained the following data:
Volume of diamond = 2.8 mL
Mass of diamond (in carat) =.?
Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:
Volume of diamond = 2.8 mL
Density of diamond = 3.51 g/mL
Mass of diamond ( in grams) =?
Density = mass /volume
3.51 = mass /2.8
Cross multiply
Mass of diamond (in g) = 3.51 × 2.8
Mass of diamond (in g) = 9.828 g
Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:
1 g = 5 carat
Therefore,
9.828 g = 9.828 g /1 g × 5 carat
9.828 g = 49.14 carat.
Therefore, the mass of the diamond in carat is 49.14 carat.