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ExtremeBDS [4]
4 years ago
5

An object is thrown up into the air going 9m/s. How fast is it going 2 seconds later?

Physics
1 answer:
Rashid [163]4 years ago
6 0

As per the question, the object is thrown in vertically upward direction.

The initial velocity of the ball [u] = 9 m/s.

We are asked to calculate the velocity of the ball after 2 second.

When the ball goes up, the only force that acts on the ball is the force of gravity.

Hence the acceleration of the ball is nothing else than acceleration due to gravity i.e g and it is downward in direction.

Here, it will be considered negative as it is downward in direction .

From equation of kinematics we know that-

                            v = u +at      [Here v is the final velocity and a is the acceleration.

                               = 9 +[-9.8]×2  m/s      [g =9.8m/s^2]

                               = 9-19.6

                               = -10.6 m/s

Here the negative sign indicates that the ball is falling downward. It is coming back after reaching its maximum height.

Here the total time of flight of the ball is-

                                           T= 2*\frac{u}{g}

                                                  = 2*\frac{9}{9.8} seconds

                                                  = 1.8367\ seconds

If the ball is thrown from certain height from the ground, then the velocity of the ball will be the calculated value.

If the ball is thrown from the ground, obviously the ball will heat the ground after 1.8367 seconds later.So the velocity of the ball will be zero after 2 seconds.

                             

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Home Run
svp [43]

The force acting on the ball are unbalanced. Reactionary momentum force (that originated as a result of the swing of the bat) is the most powerful.

Yes friction is acting on the ball. In course of journey it would slow the ball down and make it trace a parabolic path rather than straight path as intended by hitter.

Explanation:

As the hitter hits the ball, momentum of the bat due to swing (mass of the bat*velocity provided by the batsman swinging action of bat) gets transferred on the ball on its impact with the bat.

Since ball’s mass is quite small as compared to the bat, the velocity of the ball increases by the same factor by which the ball’s mass is lower than the bat’s mass. This velocity causes forward motion of the ball (of course in the direction of bat’s motion, here the batsman intends to send the ball straight away hence the ball would move straight).

Various forces on ball is-

  • Reactionary momentum force -bat’s force (most powerful force)
  • The frictional force of the air (opposing the motion of the ball through the air)
  • Gravity force (pulling the ball down to the Earth)

As a combined effect of these force when all the force remains unbalanced, the ball moves away in the straight path under the impact of bats momentum which was most powerful of all.

Frictional force and Gravity force continue acting on the ball. While frictional forces decrease the ball velocity through the air, gravity force pulls it down thus deflecting its direction. Under the combined impact of declining bats momentum, friction force and gravity force, the ball traces a parabolic path  (in accordance with the first law of motion from Newton)

8 0
4 years ago
A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A st
ANTONII [103]

Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

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3 years ago
For your senior project, you are designing a Geiger tube for detecting radiation in the nuclear physics laboratory. This instrum
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Answer:

Maximum linear charge density = 84.14 nC/m

Explanation:

Looking at this question, The electric field of a line charge of infinite length is given by : Er = (1/(2πεo)) x (λ/r)

r = the distance from the center of the line of charge

λ = the linear charge density of the wire.

Now looking at the equatiom, due to the fact that Er varies inveresely with r, its maximum value will occur at the surface of the wire where r = R, the radius of the wire:

And so, Emax = (1/(2πεo)) x (λ/R)

Let's make λ the subject of the equation and we get;

λ = 2πεo(REmax)

From the question, R = 0.55/2 = 0.275cm

Also, Emax = 5.50 × 10^(6) N/C

Let's take the value of the electric constant to be εo = 8.854 x 10^(-9) C^(2) / Nm^2

R = 0.275mm = 0.000275m

Plugging these values into the equation, we get;

λ = 2π x 8.854 x 10^(-12) x 0.000275 x 5.50 × 10^(6) = 84.14 nC/m

4 0
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Does Pascals law apply to solids?​
monitta
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Answer:

Explanation:

A unit used to measure a vector quantity is the

c) Newton

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