A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o
2 answers:
__________ _____________________
| 6 feet | | 6 feet | 6 feet |
| | | | | 4 feet
|_________ | |__________|__________|
| | |
| | | 4 feet
|__________|__________|
<span>the figure shows that the second garden has a circumference twice . We must , however, prove.
</span><span>Denote the sides of the first garden - a rectangle letters a and b
</span><span>circuit garden
C</span>₁<span> = 2a + 2b = 2*(a+b)
</span><span>The sides of the second garden also denoted with the letters a and b . We calculate the circuit
</span>C₂ = 2*2a + 2*2b = 4a + 4b = 4*(a+b)
2 = 2*100%=200%
200% -100% = 100%
Answer : The ratio of the second garden to the first ( ratio ) is 2 . <span>Circuit increased by 100 %</span>
| 6 feet | | 6 feet | 6 feet |
| | | | | 4 feet
|_________ | |__________|__________|
| | |
| | | 4 feet
|__________|__________|
<span>the figure shows that the second garden has a circumference twice . We must , however, prove.
</span><span>Denote the sides of the first garden - a rectangle letters a and b
</span><span>circuit garden
C</span>₁<span> = 2a + 2b = 2*(a+b)
</span><span>The sides of the second garden also denoted with the letters a and b . We calculate the circuit
</span>C₂ = 2*2a + 2*2b = 4a + 4b = 4*(a+b)
2 = 2*100%=200%
200% -100% = 100%
Answer : The ratio of the second garden to the first ( ratio ) is 2 . <span>Circuit increased by 100 %</span>
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Answer:
1.2%
Step-by-step explanation:
We are given that the students receive different versions of the math namely A, B, C and D.
So, the probability that a student receives version A = .
Thus, the probability that the student does not receive version A = =
.
So, the possibilities that at-least 3 out of 5 students receive version A are,
1) 3 receives version A and 2 does not receive version A
2) 4 receives version A and 1 does not receive version A
3) All 5 students receive version A
Then the probability that at-least 3 out of 5 students receive version A is given by,
+
+
=
=
=
=
= 0.01171875 × 1.0625
= 0.01245
Thus, the probability that at least 3 out of 5 students receive version A is 0.0124
So, in percent the probability is 0.0124 × 100 = 1.24%
To the nearest tenth, the required probability is 1.2%.
Answer:
The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.
Step-by-step explanation:
It is given that mean is $550, first quartile is $480, median is $630, third quartile is $700, mode is $605 and 91st percentile is $891.
First quartile is at 25% of the data, median is at 50% of the data, third quartile is at 75% of the data.
The mode of a set of data values is the value that occurs most often.
The most common salary is mode, therefore the most common salary is $605.
The salary that half the employees salaries surpass is $630. Because median is the half of the data.
The percent of employees salary that serve because $700 is 75%. Because $700 is third quartile.
Percent of employees salaries that were less than $480 is 25%. Because $480 is first quartile.
The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.
If the company has 104 employees than the total salary of employees is
because means is $550, therefore the total weekly salary of 104 employees is 57200.