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Alex
3 years ago
7

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o

f the first garden. What is the percent of change in perimeter from the first garden to the second garden?
Mathematics
2 answers:
Goshia [24]3 years ago
6 0
__________         _____________________
|    6 feet      |        |    6 feet       |     6 feet      |
|                   |        |                    |                    |    4 feet
|_________ |        |__________|__________|
                             |                    |                    |
                             |                    |                    |    4 feet
                             |__________|__________|

<span>the figure shows that the second garden has a circumference twice . We must , however, prove.
</span><span>Denote the sides of the first garden - a rectangle letters a and b
</span><span>circuit garden
C</span>₁<span> = 2a + 2b = 2*(a+b)
</span><span>The sides of the second garden also denoted with the letters a and b . We calculate the circuit
</span>C₂ = 2*2a + 2*2b = 4a + 4b = 4*(a+b)

k = \frac{ C_{2} }{ C_{1} }  =  \frac{4*(a+b)}{2*(a+b)}  =  \frac{2*(a+b)}{1}  = 2*(a+b)
 
2 = 2*100%=200%
200% -100% = 100%

Answer : The ratio of the second garden to the first ( ratio ) is 2 . <span>Circuit increased by 100 %</span>

Ulleksa [173]3 years ago
4 0
Double dimentions
perimiter

P=2(L+W)

if we have
L=6
W=4
P=2(6+4)
P=2(10)
P=20
original is 20
if both are doubled

6*2=12
4*2=8
P=2(12+8)
P=2(20)
P=40


from original to new is
from 20 to  40
what is percent  change?
find chnage
new-original=change
40-20=20
percent change=change/original
20/20=1=100%

answer is 100%
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