The mole fraction of KCl in the solution is 0.1051
calculation
mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)
moles=mass/molar mass
mass of KCl=32.7g
molar mass of KCl= 39 +35.5
moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles
find the moles of H2O= mass of H2O/molar mass
mass of H2O=100-32.7=67.3g
molar mass of H2O=( 1 x2) +16=18 g/mol
moles = 67.3/18 =3.739 moles
total moles=3.739+0.439=4.178 moles
mole fraction is therefore=0.439/4.178=0.1051
Answer:
YIKES. a bit late. Answers include 1, 2, 3
Explanation:
Ammonification refers to chemical reactions in which amino groups (NH2) associated with organic forms of nitrogen are converted into ammonia (NH3) or ammonium (NH4+).
Try this solution:
if 1 mole is 55.8 gr., then 2.25 moles the mass should be 55.8*2.25=125.55 gr.
Answer: 125.55 gr.
Answer:
A
Explanation:
balance the trades and improving them
