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In-s [12.5K]
3 years ago
12

How many molecules are there in 7.27 miles of ammonia?

Chemistry
2 answers:
worty [1.4K]3 years ago
5 0

Answer:

43.78 X 10^23

Explanation:

1 mole of NH3 has 6.023×10^23 molecules according to avogadro's principle

therefore, 7.27 moles = 6.023×10^23 X 7.27

= 43.78 X 10^23

NemiM [27]3 years ago
4 0

Hey There!

To solve this question remember that 1 mole of ammonia is equal to 17G of ammonia.

Using that, we first multiply 17 by 7 = 24

Then we multiply 7 by .27 = 1.89

Finally, taking those and adding them together gives you the answer...

<u>25.89 grams :)</u>

<u></u>

<u>Have a great day, I hope I helped.</u>

<u></u>

<u>+ Brainliest & Five stars are always appreciated </u>

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Talja [164]

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Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

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k_2 = rate constant at temperature T_2 = 4.8\times 10^8

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T_2 = temperature = 376.0^0C=(273+376)=649K

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ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]

E_a=22689.8J/mol

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3 0
3 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

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H₂  +  I₂   ⇄   2HI

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In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

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0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

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0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

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3 years ago
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