Answer:
Explanation:
The first equation of motion given as,
v = u +at
Here, u is initial and v is final velocity and a is acceleration and t is time taken.
As per question car initial velocity, u = 90 m/s, final velocity, v =0 and time taken, t = 3.00 s.
Substituting these values in first equation of motion, we get
0 = 90 m/s + a×3.00 s
or,
Thus, the deacceleration of the car is
B.
We know that the definition of acceleration is the rate of change of velocity. Moreover, velocity is a vector quantity, so it has both magnitude and direction. While moving in a circle, the direction of the car's velocity is constantly changing. This change means that the velocity of the car is changing. Because the velocity is changing, the car is accelerating, despite the magnitude of the velocity remaining the same.
1. I think it's the trails left by an electron as it moves around the nucleus.
2. The atomic number is the number of protons so it is 8.
3. It's mass is lowered but it is still the same element.
Answer:
245 N
Explanation:
Force is given by mass × acceleration. The mass is given and we need to determine the acceleration.
The bobsled starts from rest; its initial velocity is 0.0 m/s. After a distance of 6.5 m, its speed is 7.0 m/s
We use the equation of motion:
<em>v</em> is the final velocity, is the initial velocity, <em>a</em> is the acceleration and <em>s</em> is the distance.
The net force is
Answer:
<em>The Strength of the electric field produced = 2 × 10⁷ N/C</em>
Explanation:
<em>Electric Field:</em> This is defined as the region where an electric force is experienced.
<em>Electric Field Strength: </em><em>The intensity of an electric field at any point is defined as the force per unit charge which it exert at that point. It direction is that of the force exerted on a positive charge.</em>
<em>It is represented mathematically as,</em>
<em>E = F/Q ................................. Equation 1</em>
<em>Where E = Electric field strength, F = electric force, Q = test charge.</em>
<em>Given: F = 3.2 × 10⁻⁴ N, Q = 1.6 × 10⁻¹¹ C</em>
<em>Substituting these values into equation 1</em>
<em>E= 3.2 × 10⁻⁴/1.6 × 10⁻¹¹ </em>
<em>E= 2 × 10⁷ N/C</em>
<em>Thus the Strength of the electric field produced = 2 × 10⁷ N/C</em>
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