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bonufazy [111]
3 years ago
8

You have a gas at a volume of 9.71 L at a pressure of 209 torr and at 10.1 °C. What

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

219.95 °C

Explanation:

Given data:

Volume of gas = 9.71 L

Initial pressure = 209 torr (209/760 = 0.275 atm)

Initial temperature = 10.1 °C (10.1 +273 = 283.1 K)

Final temperature = ?

Final pressure = 364 torr (364/760 =0.479 atm)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.275 atm / 283.1 K = 0.479 atm/T₂

T₂ = 0.479 atm × 283.1 K/ 0.275 atm

T₂ = 135.6 atm. K /0.275 atm

T₂ = 493.1 K

Kelvin to °C:

493.1 K - 273.15 = 219.95 °C

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Answer:

One

Explanation:

In H2O, there's 2 hydrogen atoms and 1 oxygen atom

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3 years ago
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kramer

Answer:

A.

Explanation:

In an endothermic reaction heat is applied.

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g Reduction involves the A) loss of neutrons, gain of electrons, and an increase in oxidation state. B) loss of neutrons. C) inc
artcher [175]

Answer:

E. Gain of electrons

Explanation:

A reduction reaction is one part of the two concurrent reactions that take place in a redox (reduction-oxidation) reaction.

During reduction, an atom gains electrons from a donor atom, and it's oxidation number becomes smaller.

Option A is wrong because reduction does not increase oxidation state nor are neutrons involved

Option B is wrong because reduction is not a nuclear reaction (does not involve the nucleons)

Option C is wrong because reduction leads to reduction in oxidation state

Option D is wrong leads to a reduction in oxidation state when electrons are gained

Option E is correct because reduction involves gain of electrons

4 0
3 years ago
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Andreas93 [3]

Answer:

A.)

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The first structure accurately represents ethyl ethanoate because there is an ethyl group (2 carbons) directly attached to the oxygen within the parent chain and there are 2 carbons (the eth- in ethanoate) attached to the  double bonded oxygen.

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3 0
2 years ago
A 1.50 g sample of solid NH₄NO₃ was added to 35.0 mL of water in a styrofoam cup (insulated from the environment) and stirred un
GaryK [48]

Answer : The heat of the reaction is, 1.27 kJ/mole

Explanation :

First we have to calculate the heat released.

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of sample = 1.50 g

c = specific heat of water = 4.81J/g^oC

T_1 = initial temperature  = 22.7^oC

T_2 = final temperature  = 19.4^oC

Now put all the given value in the above formula, we get:

Q=1.50g\times 4.81J/g^oC\times (19.4-22.7)^oC

Q=-23.8095J=-0.0238kJ

Now we have to calculate the heat of the reaction in kJ/mol.

\Delta H=\frac{Q}{n}

where,

\Delta H = enthalpy change = ?

Q = heat released = 0.0238 kJ

n = number of moles NH₄NO₃ = \frac{\text{Mass of }NH_4NO_3}{\text{Molar mass of }NH_4NO_3}=\frac{1.50g}{80g/mol}=0.01875mole

\Delta H=\frac{0.0238kJ}{0.01875mole}=1.27kJ/mole

Therefore, the heat of the reaction is, 1.27 kJ/mole

8 0
3 years ago
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