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2 years ago

You have a gas at a volume of 9.71 L at a pressure of 209 torr and at 10.1 °C. What

Chemistry

1 answer:

Usimov [2.4K]2 years ago

8 0

Answer:

219.95 °C

Explanation:

Given data:

Volume of gas = 9.71 L

Initial pressure = 209 torr (209/760 = 0.275 atm)

Initial temperature = 10.1 °C (10.1 +273 = 283.1 K)

Final temperature = ?

Final pressure = 364 torr (364/760 =0.479 atm)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

0.275 atm / 283.1 K = 0.479 atm/T₂

T₂ = 0.479 atm × 283.1 K/ 0.275 atm

T₂ = 135.6 atm. K /0.275 atm

T₂ = 493.1 K

Kelvin to °C:

493.1 K - 273.15 = 219.95 °C

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In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe

ad-work [718]

We know the law of conservation of mass

It states that mass is neither formed nor destroyed in any chemical reaction.
Mass of reactants=Mass of products.

Here

Mg and I_2 are reactants
MgI_2 is product with some yield.
Mass of reactants=10+60.0=70.0g
Mass of MgI_2=53.88g
Mass of yield=Product-MgI_2=70-53.88=16.12g

Lets find the percentage

$\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100$

$\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100$

$\\ \tt\hookrightarrow 0.23028(010)=23.028\%$

6 0

1 year ago

Read 2 more answers

As white light passes through a prism, the light is ____<br><br> A. Reflected <br> B. Refracted

noname [10]

Answer:

Refracted

Explanation:

White light refracts when it passes through a prism. Each wavelength refracts at a different angle, and the emergent light forms a rainbow.

3 0

2 years ago

Read 2 more answers

Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r

Alenkasestr [34]

<h2>1.25 g of $CO_2$ would be produced from the complete reaction of 25 mL of 0.833 mol/L $HC_3H_3O_2$ with excess $NaHCO_3$ </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

$0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol$

$NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2$

According to stoichiometry:

1 mole of $HC_2H_3O_2$ will give = 1 mole of $CO_2$

0.0208 moles of $HC_2H_3O_2$ will give = $\frac{1}{1}\times 0.0208=0.0208 moles$ of $CO_2$

Mass of $HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g$

Thus 1.25 g of $CO_2$ would be produced from the complete reaction of 25 mL of 0.833 mol/L $HC_3H_3O_2$ with excess $NaHCO_3$

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5 0

2 years ago

Why do you think that the electrons are not shown?

snow_lady [41]

Because there to tiny to see

7 0

2 years ago

811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of

Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

Provided heat (Q): 811.68 J

Mass of the metal (m): 95 g

Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0

2 years ago