Answer:
The corresponding p-value, is p = 1
Step-by-step explanation:
The maximum score SAT score, n = 1,600
The mean of the district's total SAT score distribution = 1,200
The claim of one of the districts principal, is the that mean of the district's total SAT score distribution ≠ 1,200
Using proportions, we have;
p = 1,200/1,600 = 0.75
q = 1 - p = 0.25
The margin of error, E = Z√(p·q/n)
∴ E = 5% = Z×√((0.75 × 0.25)/1,600)
z = 0.05/(√((0.75 × 0.25)/1,600)) ≈ 4.61880
Therefore, the corresponding p-value, p = 1
