The amount of energy released or absorbed as heat during a chemical reaction is called __________

Which of the following is true about the two atoms below?

nordsb [41]

Answer:

Different Number of neutrons.

4 0

3 years ago

What is the amount of mass in each given unit of volume?

labwork [276]

Answer:

Each volumn is different and therefore has a specific and unique mass.

3 0

3 years ago

Consider the acid-base neutralization reaction H2S(aq) + CN‒(aq) ⇌ HS‒(aq) + HCN(aq) For H2S, pKa = 7.0, and for HCN, pKa = 9.4.

zubka84 [21]

Answer:

(c) At equilibrium, the equilibrium position favors the reactants.

Explanation:

To assess the strength of an acid or a base we need to consider the pKa or pKb. For an acid, the lower the pKa, the stronger the acid. For a base, the lower the pKb, the stronger the base.

<em>Which of the following statements is FALSE?</em>

<em>(a) H₂S is a stronger acid than HCN.</em> TRUE. The pKa of H₂S (7.0) is lower than the pKa of HCN (9.4).

<em>(b) CN⁻ is a stronger base than HS⁻.</em> TRUE. We can calculate the pKb of a base when we know the pKa of the conjugate acid using the following expression:

pKa + pKb = 14 ⇒ pKb = 14 - pka

The pKb of CN⁻ (4.6) is lower than the pKb of HS⁻(7.0) so it is a stronger base.

<em>(c) At equilibrium, the equilibrium position favors the reactants.</em> FALSE. In the reaction H₂S(aq) + CN⁻(aq) ⇌ HS⁻(aq) + HCN(aq), H₂S is the stronger acid and CN⁻ is the stronger base, so at the equilibrium the products are favored.

(d) At equilibrium, the equilibrium constant, Kc, is larger than 1. TRUE. Given the products are favored at the equilibrium, the equilibrium constant Kc is expected to be larger than 1 (the numerator is higher than the denominator).

5 0

3 years ago

Please help me i will give brain list

Strike441 [17]

Answer:

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3 0

3 years ago

Read 2 more answers

What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane

Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂ ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3 moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0

3 years ago

The amount of energy released or absorbed as heat during a chemical reaction is called ___________.