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myrzilka [38]
3 years ago
13

What is the mass of 53 ml of ethanol, which has a density of 0.79 g/ml?

Physics
2 answers:
Georgia [21]3 years ago
8 0
Density=mass/volume 
0.79=53/x
x=67.09
Hope this helps!
Iteru [2.4K]3 years ago
5 0

Answer:

m = 41.87 g

Explanation:

As we know that mass of an object is product of its density and volume

so we can say that

m = \rho V

here we know that

\rho = 0.79 g/mL

also we know that

V = 53 mL

now by above formula we have

m = 0.79 \times 53

m = 41.87 g

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A positive rod is touched to a neutral sphere. There is a bar with positively charged particles attached to a ball with positive
solong [7]

Answer: A is correct

It is showing the direction that protons move in, making the sphere negative

Explanation:

From the figure, since the charges on the rod are completely positive, it shows that the protons are transferring from the sphere to the rod leaving the rod negatively charged.

Therefore, It is showing the direction that protons move in, making the sphere negative.

4 0
3 years ago
2. A 1.54 kΩ resistor is connected to an AC voltage source with an rms voltage of 240 V.
svp [43]

(a) The maximum potential difference across the resistor is 339.41 V.

(b) The maximum current through the resistor is 0.23 A.

(c) The rms current through the resistor is 0.16 A.

(d)  The average power dissipated by the resistor is 38.4 W.

<h3>Maximum potential difference</h3>

Vrms = 0.7071V₀

where;

  • V₀ is peak voltage

V₀ = Vrms/0.7071

V₀ = 240/0.7071

V₀ = 339.41 V

<h3> rms current through the resistor </h3>

I(rms) = V(rms)/R

I(rms) = (240)/(1,540)

I(rms) = 0.16 A

<h3>maximum current through the resistor </h3>

I₀ = I(rms)/0.7071

I₀ = (0.16)/0.7071

I₀ = 0.23 A

<h3> Average power dissipated by the resistor</h3>

P = I(rms) x V(rms)

P = 0.16 x 240

P = 38.4 W

Learn more about maximum current here: brainly.com/question/14562756

#SPJ1

8 0
2 years ago
HELP PLEASE !!
Umnica [9.8K]
If a car crashes into another car like this, the wreck should go nowhere. Besides this being an unrealistic question, the physics of it would look like this:

Momentum before and after the collision is conserved.

Momentum before the collision:
p = m * v = 50000kg * 24m/s + 55000kg * 0m/s = 50000kg * 24m/s
Momentum after the collision:
p = m * v = (50000kg + 55000kg) * v

Setting both momenta equal:
50000kg * 24m/s = (50000kg + 55000kg) * v

Solving for the velocity v:
v = 50000kg * 24m/s/(50000kg + 55000kg) = 11,43m/s

3 0
3 years ago
Which type of experiment involves changing only one variable at a time
BlackZzzverrR [31]
Controlled Experiment 

6 0
3 years ago
Read 2 more answers
5. Find the mass of a car that is traveling at a velocity of 35 m/s West.
sattari [20]

Answer:

m = 9795.9 kg

Explanation:

v = 35 m/s

KE = 6,000,000 J

Plug those values into the following equation:

KE = \frac{1}{2} mv^{2}

6,000,000 J = (1/2)(35^2)m

---> m = 9795.9 kg

3 0
3 years ago
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