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2 years ago

What is the mass of 53 ml of ethanol, which has a density of 0.79 g/ml?

Physics

2 answers:

Georgia [21]2 years ago

8 0

Density=mass/volume
0.79=53/x
x=67.09
Hope this helps!

Iteru [2.4K]2 years ago

5 0

Answer:

m = 41.87 g

Explanation:

As we know that mass of an object is product of its density and volume

so we can say that

$m = \rho V$

here we know that

$\rho = 0.79 g/mL$

also we know that

$V = 53 mL$

now by above formula we have

$m = 0.79 \times 53$

$m = 41.87 g$

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What is the energy of a photon with a frequency of 3. 6 × 1015 hz? planck’s constant is 6. 63 × 10–34 j•s.

GrogVix [38]

Answer:

2.029×10^-18 J

Explanation:

E=hv

E=(3.06×10^15)*(6.63×10^-34)

E=2.029×10^-18 J

3 0

2 years ago

A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?

Kaylis [27]

The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

CALCULATE INITIAL VELOCITY:

The initial velocity of the car can be calculated by using one of the equation of motion as follows:

V = u + at

Where;

V = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration due to gravity (m/s²)
t = time (s)

According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:

u = v - at

u = 27 - 3(5)

u = 27 - 15

u = 12m/s.

Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

Learn more about motion at: brainly.com/question/974124

4 0

2 years ago

An 80kg astronaut traveled to the moon, where gravity is one-sixth (116) as

PIT_PIT [208]

Answer:

Wmoon = 131 [N]

Explanation:

We know that the weight of a body is equal to the product of mass by gravitational acceleration.

Since we are told that the gravitational acceleration of the moon is equal to one-sixth of the acceleration of Earth's gravitation. Then we must multiply the value of Earth's gravitation by one-sixth.

$w_{moon}=\frac{1}{6} *m*g\\w_{moon}=\frac{1}{6} *80*9.81\\w_{moon}=130.8 [N] = 131 [N]$