<span>Energy is transported from the ocean to the atmosphere which makes the atmosphere cooler.</span>
Answer:
sulfurous acid with lithium hydroxide to form water and lithium sulfite. The balanced reaction equation is b. H2SO3(aq) + 2 LiOH(aq) → 2 H2O(l) + Li2SO3(aq).
The answer is pH = 7.37.
Solution:
First, we set up an ICE table for the reaction:
F- + H2O → HF + OH-
Initial 0.00378 0 0
Change -x +x +x
Equilibrium 0.00378-x x x
We can calculate Kb from the given Ka, since we know that Kw = Ka*Kb = 1.0 x 10^-14 at 25°C:
Kb = Kw/Ka = 1.0x10^-14 / 6.80x10^-4 = 1.471 x 10^-11
Kb = 1.471 x 10^-11 = [OH-][HF] / [F-] = (x)(x) / (0.00378-x)
Approximating that x is negligible compared to 0.00378 simplifies the equation to
1.471x10^-11 = (x)(x) / 0.00378
1.471 x 10-11 = x2 / 0.00378
Then we solve for x that is also equal to [OH-]:
x2 = (1.471 x 10^-11)(0.00378)
x = sqrt[(1.471 x 10^-11)(0.00378)] = 2.358x10^-7 = [OH-]
in which 0.0000002358 is indeed negligible compared to 0.00378.
We can now calculate for pOH:
pOH = -log [OH-] = -log (2.358x10^-7) = 6.63
Therefore, the pH is
pH = 14 - pOH = 14 - 6.63 = 7.37
Answer:
Use stoichiometry to find your answers
Explanation:
Answer:
22387Fr→22388Ra+0−1e+00ν
Explanation:
β-decay is the decay of a neutron into a proton, which keeps the total mass the same, but increases the number of protons by 1. β-decay does this by releasing an electron, which conserves charge, and a neutrino.
Francium-223 has an atomic number of 87, so is written as
22387Fr
If the atomic number then increases by 1 to become 88, then it is a new element. Looking at the periodic table, element 88 is radium, Ra.
In the form of an equation, this is shown as
22387Fr→22388Ra+0−1e+00ν
You can check this is correct by adding up the top numbers on each side and equating them, and doing the same with the bottom numbers.
223=223+0+0
87+88+(−1)+0
