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Law Incorporation [45]
3 years ago
6

Triangle W Z Y is cut by bisector Z X. The lengths of sides Z W and Z Y are congruent. ZX bisects ∠WZY. If the measure of ∠YXZ i

s (6m – 12)°, what is the value of m?

Chemistry
2 answers:
stepan [7]3 years ago
7 0

Answer:

m = 17

Explanation:

From the question we were given that

Triangle WZY is bisected by ZX; ZW = ZY

∠YXZ = (6m – 12)°

Based on the characteristics of the triangle, we see that triangle WYZ is an isosceles triangle (that is, triangle WXZ is equal to triangle YXZ)

<YXZ = <WXZ = 90°

Using ∠YXZ  = (6m – 12)°

We have:

(6m – 12)° =  90°

6m = 90 + 12 ⇒ 6m = 102

m = 102 ÷ 6 = 17

m = <u>17</u>

<u>We therefore see that m is equal to 17</u>

mixas84 [53]3 years ago
3 0

Answer:

B: <u><em>17 </em></u>

Explanation:

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Analysis of a compound indicates that it contians 1.04 g K, 0.70 g Cr, and 0.86 g O. Find its empirical formula.
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Answer:

K2CrO4

Explanation:

To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:

K = 1.04/39.0983 = 0.027

Cr = 0.70/51.9961 = 0.013

O = 0.86/15.999 = 0.054

We now divide by the smallest which is the number of moles of the Chromium

K = 0.027/0.013 = 2

Cr = 0.013/0.013 = 1

K = 0.054/0.013 = 4 approximately

The empirical formula is thus:

K2CrO4

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3 years ago
Eq-43 which type of fire extinguisher should be onboard a vessel with a permanently installed fuel tank
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I think a type B fire extinguisher should be on board a vessel with a permanently installed fuel tank. 
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4 years ago
Isotopes of the same element differ in their number of?
SCORPION-xisa [38]

Answer:

Neurons

Explanation:

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4 0
3 years ago
How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

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This is the reaction:

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Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

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