All categories

4 years ago

A substance with a pH of 4.0 will

Physics

2 answers:

eimsori [14]4 years ago

5 0

PH of 4 is Acidic and its property is to turn blue litmus red

Nat2105 [25]4 years ago

5 0

It changes blue to red, Hope it helped :)

You might be interested in

A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.

Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is $\mu _{k} =$ 0.12</h3>

Explanation:

Given :

Initial speed $v_{o} = 9.5 \frac{m}{s}$

Displacement $x = 37.4$ m

From the kinematics equation,

$v^{2} - v^{2} _{o} = 2ax$

Where $v^{2} =$ final velocity, in our example it is zero ( $v =0$ ), $a =$ acceleration.

$a =- \frac{90.25}{ 2 \times 37.4}$

$a =- 1.21 \frac{m}{s^{2} }$

From the formula of friction,

$F =- \mu _{k } N$

Minus sign represent friction is oppose the motion

Where $N = mg$ ( normal reaction force )

$ma = -\mu _{k} m g$ ( ∵ $g = 9.8 \frac{m}{s^{2} }$ )

So coefficient of friction,

$\mu_{k} = \frac{1.21}{9.8}$

$\mu_{k} = 0.12$

Therefore, the coefficient of kinetic friction between the puck and the ice is $\mu _{k} =$ 0.12 .

4 0

3 years ago

A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci

larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 = e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

#SPJ1

6 0

2 years ago

A disk between vertebrae in the spine is subjected to a shearing force of 425 N. Find its shear deformation, taking it to have a

zzz [600]

Answer:

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm and diameter = 6.50 cm

$\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta = 5.27 \times 10^{-7} m$

hence, the correct answer is option A

3 0

4 years ago

Your friend has slipped and fallen. To help her up, you pull with a force F, as the drawing shows. The vertical component of thi

sineoko [7]

This question can be solved using the concept of the composition of the vector.

(a) The magnitude of F is b "164.27 N".

(b) The angle of the vector from horizontal is " ".

(a)

From the composition of the rectangular components of a vector, we know that the magnitude of the resultant vector is given by the following formula:

$F = \sqrt{F_x^2+F_y^2}$