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Elden [556K]
2 years ago
5

A package of chips weighs 45 grams. How much is that in kilograms?

Chemistry
1 answer:
Slav-nsk [51]2 years ago
5 0

Answer:

1000g=1kg

45g=?

45/1000

0.045kilograms

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Which of the following measurements is equal to 2,300 dL
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3 years ago
If a cold piece of metal is added to hot water, the water will
Roman55 [17]

Answer:

Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature

Explanation:

5 0
3 years ago
Needed help plzzz on this chemistry homework.
mrs_skeptik [129]
Hertz is units for frequency. (waves per second)
wavelength = speed/frequency

if you're given the speed use that to calculate, if not then you can probably assume it's a wave of light and use the speed of light (3x10^8 m/s) to calculate.

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5 0
2 years ago
Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energ
SSSSS [86.1K]

<u>Answer:</u> The molecules of oxygen gas that will be reduced to water are 42 molecules

<u>Explanation:</u>

We are given:

E^o_{(NO_2^-/NH_4)}=-0.41V\\E^o_{(O_2/H_2O)}=0.82V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, oxygen will undergo reduction reaction will get reduced.

NH_4 will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

The half reactions follows:

<u>Oxidation half reaction:</u>  NH_4\rightarrow NO_2^-+6e^-     ( × 4)

<u>Reduction half reaction:</u>  O_2+4e^-\rightarrow 2H_2O   ( × 6)

<u>Overall reaction:</u> 4NH_4+6O_2\rightarrow 4NO_2^-+12H_2O

We are given:

Molecules of NH_4 = 28

By Stoichiometry of the reaction:

4 molecules of NH_4 reacts with 6 molecules of oxygen gas

So, 28 molecules of NH_4 will react with = \frac{6}{4}\times 28=42 molecules of oxygen gas

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4 0
3 years ago
Can someone help Plz
Marrrta [24]

Answer: A. 1.60 liters

Explanation:

2Na_2O_2+2CO_2\rightarrow 2Na_2CO_3+O_2

As can be seen from the balanced chemical equation, 2 moles of CO_2 produce 1 mole of O_2.

According to Avogadro's law, every 1 mole of the gas occupies 22.4 liters at STP.

Thus 2 moles of CO_2 occupies 22.4\times 2=44.8L at STP and produce 1 mole of O_2 i.e. 22.4 L

44.8 L of CO_2 will produce 22.4 L of O_2

Thus 3.20L of CO_2 will produce \frac{22.4}{44.8}\times 3.20=1.60L



6 0
2 years ago
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