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Elden [556K]
2 years ago
5

A package of chips weighs 45 grams. How much is that in kilograms?

Chemistry
1 answer:
Slav-nsk [51]2 years ago
5 0

Answer:

1000g=1kg

45g=?

45/1000

0.045kilograms

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Technetium-99 is an ideal radioisotope for scanning organs because it has a half-life of 6.0 h and is a pure gamma emitter. supp
Nadusha1986 [10]

Answer: 20 mg Te-99 remains after 12 hours.

Explanation:  N(t) = N(0)*(1/2)^(t/t1/2)

                        N(t) = (80 mg)*(0.5)^(12/6)

N(t) = 20 mg remains after 12 hours

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Q05 the "atomic number" of an atom is determined by the number of ________ it has.
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The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table 
6 0
3 years ago
What is the Method for distillation?
a_sh-v [17]
Distillation is a process of separating the component substances from a liquid mixture by selective evaporation and condensation. 
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A block of metal has a mass of 0.0694 kg. It displaces 3.6 mL of water. What is it’s density in g/cm^3
Ivan

Answer:

19.28 g/cm^3 to the nearest hundredth.

Explanation:

The volume of water displaced = the volume of the metal.

density = mass / volume

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=  69.4 g.

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= 19.28 g/cm^3.

4 0
3 years ago
A methanol-water mixture is to be flash distilled at 1 atm. If the feed is 25 mole %methanol, what are the liquid and vapor comp
frozen [14]

Answer:

Explanation:

Given that:

The distillation is carried out at a pressure of 1 atm

The feed harbors 25% mole of methanol (z)

The total moles of feed is usually 100 moles

In the system, we have both methanol and water

Using the total mole balance for the distillation column.

Fz = Lx + Vy

where;

F = amount of feed

z = mole fraction of ethanol (in feed)

L = amount of liquid product out of the column

V = amount of vapor product out of the column

x = mole fraction of methanol out of the liquid

y  = mole fraction of methanol out of the vapor.

SO;

(a)

If all the feed is vaporized, then the vapor will likely have the same composition as the feed.

(b)

If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.

(c)

If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.

The balance equation would be:

Fz = (\dfrac{2}{3}F) x + (\dfrac{1}{3}F)y \\ \\ z = \dfrac{2}{3}x+\dfrac{1}{3}y

Replacing z = 0.25; we have:

0.25 = \dfrac{2}{3}x+\dfrac{1}{3}y

0.75 = 2x + y

(d)

If 2/3 of the feed is vaporized;

Then:

Fz = (\dfrac{1}{3}F) x + (\dfrac{2}{3}F)y \\ \\ z = \dfrac{1}{3}x+\dfrac{2}{3}y

replacing z = 0.25

0.25 = \dfrac{1}{3}x+\dfrac{2}{3}y

0.75 = x + 2y

6 0
2 years ago
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