Answer:
See explanation and image attached
Explanation:
My aim is to convert 1-bromobutane to butanal. The first step is to react the 1-bromobutane substrate with water. This reaction occurs by SN2 mechanism to yield 1-butanol. Hence reagent A is water.
1-butanol is now reacted with an oxidizing agent such as acidified K2Cr2O7 (reagent B) to yield butanal. Note that primary alkanols are oxidized to alkanals.
These sequence of reactions are shown in the image attached.
Answer:
The initial temperature of helium was T1 = 232.23 K
Explanation:
Given data:
Initial volume V1 = 5 L
Initial pressure P1 = 699 mmHg
Final pressure P2 = 800 mmHg
Final volume V2 = 5.7 L
Final temperature T2= 303 K
Initial temperature T1 = ?
Solution:
Formula:
P1V1/T1 = P2V2/T2
T1 = T2 × P1V1/P2V2
T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L
T1 = 1058985/ 4560
T1 = 232.23 K
initial temperature of helium was 232.23 k.
Carbon disulfide is prepared by heating sulfur and charcoal. the chemical equation is S2(g) + C(s) <---> CS2 (g) Kc = 9.40 at 900 K.
Hope this helps:)
