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nalin [4]
1 year ago
8

In the four terrestrial planets, the densest, heaviest materials are at the center and not evenly distributed throughout the pla

net. Scientists interpret this observation to mean that:
Physics
1 answer:
Gala2k [10]1 year ago
3 0

<em>The question is incomplete. Please read below the missing content.</em>

B) The 4 terrestrial planets have to as soon as were hot sufficient to be molten (like a liquid).

Terrestrial planets may be described as any planet of the sun machine or any exoplanet that is "Earth-like" in the experience that it is composed primarily of metals and rock, in evaluation to a planet that's a fuel large.

In the sun machine, the terrestrial planets are the inner planets closest to the solar, i.e. Mercury, Venus, Earth, and Mars.

Scientists believe that the densest, heaviest substances are at the center and not evenly allotted can be due to the truth that they need to once be warm enough to be molten. In this example, density will take region, making the heavier below and the lighter on the pinnacle.

In the four terrestrial planets, the densest, heaviest materials are at the center and not evenly distributed throughout the planet. Scientists interpret this observation to mean that:

a.the four terrestrial planets must once have been inside the Sun

b.the four terrestrial planets must once have been hot enough to be molten (like a liquid)

c.the four terrestrial planets must have formed where Jupiter and Saturn now are

d.the four terrestrial planets must have collided with each other many times

e.none of the above

Learn more about terrestrial planets here brainly.com/question/11862047

#SPJ4

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When observing an object, you determine it is moving at a constant velocity and in a straight line. Which of these BEST describe
Marina86 [1]
The answer would be C. Hope this helps XD
8 0
3 years ago
Read 2 more answers
A system consists of electrons and protons only. It contains 150 electrons and has a total charge of +22e. What is the mass of t
liubo4ka [24]

According to the statements the number of electrons is 150, then

e = 150

But there is a positive charge of +22e, then the number of protons would be

p = 150+172

If the mass of the electrons is

m_e = 9.11*10^{-31} kg

And the mass of the protong is

m_p = 1.673*10^{-27}kg

We have that the total mass of the system would be

m = e*m_e +pm_p

m = 150 * (9.11*10^{-31})+170(1.673*10^{-27})

m = 2.84547*10^{-25} kg

5 0
3 years ago
A 5000-lb wrecking ball hangs from a 50-ft cable of density 10 lb/ft attached to a crane. Calculate the work done if the crane l
aniked [119]

Answer:

total work is = 52450 J

Explanation:

given data

mass =  5000-lb

density = 10 lb/ft

height = 50 ft

solution

as we will treat here cable and ball are separate  

and

here work need to lift cable is

w = (10Δy )(9.8 y )  j

and

now summing all segment of cable

so passing limit Δy to 0

so total work need

= \int\limits^{10}_0 {98y} \, dy    

= [49 y^2]^{50}_0

= 2450J

so lifting 5000 lb wrcking 50 m  required additional 5000 + 2450

so total work is = 52450 J

3 0
3 years ago
A particle with a charge of -4.0 μC and a mass of 3.2 x 10-6 kg is released from rest at point A and accelerates toward point B,
Assoli18 [71]

Answer:

V_B-V_A=-20736-0=-20736volt

Explanation:

We have given charge on the particle q=-4\mu C=-4\times 10^{-6}C

Mass of the charge particle m=3.2\times 10^{-6}kg

From energy of conservation kinetic energy will be equal to potential energy

So at point A

\frac{1}{2}mv^2=qV

At point a velocity is zero

So \frac{1}{2}(3.2\times10^{-6} )0^2=-4\times 10^{-6}V_a

V_A=0volt

At point B velocity will be 72 m/sec

So \frac{1}{2}\times 3.2\times 10^{-6}72^2=-4\times 10^{-6}V_b

V_B=-20736volt

So V_B-V_A=-20736-0=-20736volt

4 0
3 years ago
A 34 kg bowling ball with a radius of 22 cm starts from rest at the top of an incline 4.4 m in height. Find the translational sp
liberstina [14]

Answer:

7.85 m/s.

Explanation:

Given,

Mass of the bowling ball, m = 34 Kg

radius, r = 0.22 cm

height of the inclination, h = 4.4 m

transnational velocity = ?

Moment of inertia of bowling ball,

I = \dfrac{2}{5}mr^2

Using conservation of energy

mgh = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2

We know that v = r\omega

mgh = \dfrac{1}{2}( \dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2

m gh = 0.7 m v^2

v =\sqrt{\dfrac{gh}{0.7}}

v =\sqrt{\dfrac{9.81\times 4.4}{0.7}}

v = 7.85\ m/s

Speed of the bowling ball is equal to 7.85 m/s.

3 0
3 years ago
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