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nalin [4]
1 year ago
8

In the four terrestrial planets, the densest, heaviest materials are at the center and not evenly distributed throughout the pla

net. Scientists interpret this observation to mean that:
Physics
1 answer:
Gala2k [10]1 year ago
3 0

<em>The question is incomplete. Please read below the missing content.</em>

B) The 4 terrestrial planets have to as soon as were hot sufficient to be molten (like a liquid).

Terrestrial planets may be described as any planet of the sun machine or any exoplanet that is "Earth-like" in the experience that it is composed primarily of metals and rock, in evaluation to a planet that's a fuel large.

In the sun machine, the terrestrial planets are the inner planets closest to the solar, i.e. Mercury, Venus, Earth, and Mars.

Scientists believe that the densest, heaviest substances are at the center and not evenly allotted can be due to the truth that they need to once be warm enough to be molten. In this example, density will take region, making the heavier below and the lighter on the pinnacle.

In the four terrestrial planets, the densest, heaviest materials are at the center and not evenly distributed throughout the planet. Scientists interpret this observation to mean that:

a.the four terrestrial planets must once have been inside the Sun

b.the four terrestrial planets must once have been hot enough to be molten (like a liquid)

c.the four terrestrial planets must have formed where Jupiter and Saturn now are

d.the four terrestrial planets must have collided with each other many times

e.none of the above

Learn more about terrestrial planets here brainly.com/question/11862047

#SPJ4

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what happens to a circuits resistance, voltage, and current when you increase the diameter of the wire in the circuit?
zhannawk [14.2K]

Answer:

Option D.

Resistance (R) decreases

Voltage (V) is constant

Current (I) increases

Explanation:

We'll begin by writing an equation relating resistance and diameter of a wire. This is given below:

R = ρL/A ......... (1)

A = πr² (since the wire is circular in shape)

r = d/2

A = πr² = π(d/2)²

A = πd²/4

Substitute the value of A into equation 1

R = ρL/A

R = ρL ÷ A

R = ρL ÷ πd²/4

R = ρL × 4/πd²

R = 4ρL /πd²

Where:

R is the resistance of the wire.

ρ is the resistivity of the wire.

L is the length of the wire.

A is the cross sectional area of the wire.

r is the radius.

d is the diameter of the wire

From equation (1) above, we can say that the resistance (R) is inversely proportional to the square of the diameter of the wire. This implies that an increase in the diameter of the wire will result in a decrease of the resistance. Also, a decrease in the diameter of the wire will result in an increase in the resistance of the wire.

1. Since the diameter of the wire is increase, therefore, the resistance of the wire will decrease.

2. From ohm's law,

V = IR

Divide both side by I

R = V/I

Where:

R is the resistance

V is the voltage

I is the current

From the above equation, the resistance (R) is directly proportional to the voltage (V) and inversely proportional to the current (I).

If we keep the voltage constant, this means that an increase in the resistance will lead to a decrease in the current. Also, a decrease in the resistance will lead to an increase in the current.

Since the resistance of the wire decrease, the current will increase.

From the illustrations made above, an increase in the diameter of the wire will lead to:

1. Decrease in resistance.

2. Voltage is constant.

3. Increase in current.

5 0
3 years ago
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