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DiKsa [7]
4 years ago
12

Scallops use jet propulsion to move from one place to another. Their shells make them denser than water, so they normally rest o

n the ocean floor.
If a scallop wishes to remain stationary, hovering a fixed distance above the ocean floor, it must eject water _____ so that the thrust force on the scallop is _____.

a) upward; upward
b) upward; downward
c) downward; upward
d) downward; downward
Physics
1 answer:
Paha777 [63]4 years ago
5 0

Answer:

c

Explanation:

Since he shells of scallops make them denser than water, they normally rest on the ocean floor, which means there is a force needed to overcome the gravitational pull, which pullls them towards the ocean flootr. To hover in the water they must use their yet propulsion to push upwards ( otherwise they sink to the floor again).

To be able to create an upward force, the yet propulsion needs to eject water downwards. Every action has the same and opposite reaction (Third law of Newton).

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List how many significant figures the numbers contain. A. 205 cm. B. .00004 cm. C. 20 cm. D. 20. Cm.
stiv31 [10]
A. 205 cm
   This has 3 significant figures: 2,0 and 5.

B. 0.00004 cm
   This has 1 significant figure: 4

C. 20 cm
   This has 2 significant figures: 2 and 0.

D. 20. cm
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Which type of surface is best for absorbing sound waves?
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I believe it is D) foam
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The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.
Lisa [10]

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6 0
3 years ago
A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
How much current will pass through a 12.5 ohm resistor when it is connected to ta 115 volt source of electrical potential?
Marrrta [24]

Answer:

9.2 amperes

Explanation:

Ohm's law states that the voltage V across a conductor of resistance R is given by V = R I

Here, voltage V is proportional to the current I.

For voltage, unit is volts (V)

For current, unit is amperes (A)

For resistance, unit is Ohms (Ω)

Put R = 12.5 and V = 115 in V=RI

115=12.5I\\I=\frac{115}{12.5}\\ =9.2\,\,amperes

8 0
4 years ago
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