in order to decrease the freezing point of 500. g of water to 1.00° c how many grams of ethylene glycol (C2H602)must be added (K
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Answer : The heat of this reaction of AgCI formed will be, 66.88 KJ
Explanation :
First we have to calculate the heat of the reaction.
where,
q = amount of heat = ?
= specific heat capacity =
m = mass of substance = 120 g
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the number of moles of and
.
Now we have to calculate the limiting reactant.
The balanced chemical reaction will be,
As, 1 mole of react with 1 mole of HCl
So, 0.006 mole of react with 0.006 mole of HCl
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of AgCl.
The given balanced reaction is,
From this we conclude that,
1 mole of react with 1 mole
to produce 1 mole of
0.006 mole of react with 0.006 mole
to produce 0.006 mole of
Now we have to calculate the heat of this reaction of AgCI formed.
As, 0.006 mole of AgCl produced the heat = 401.28 J
So, 1 mole of AgCl produced the heat =
Therefore, the heat of this reaction of AgCI formed will be, 66.88 KJ