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3 years ago

If a solution has a pOH of 8.71, what is the [H+]?

Chemistry

1 answer:

TEA [102]3 years ago

6 0

Answer: $5.1\times 10^{-6}M$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH+pOH=14$

Putting in the values:

$pH=14-8.71=5.29$

$5.29=-log[H^+]$

$[H^+]=5.1\times 10^{-6}$

Thus $[H^+]$ is $5.1\times 10^{-6}M$

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How did lavoisier revolutionize the science in chemistry

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3 years ago

The ph of a fruit juice is 3.2. find the hydronium ion concentration, left bracket upper h 3 upper o superscript plus right bra

melomori [17]

pH is referred to as the scale to describe the hydronium ion concentration of a

solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.

pH can be calculated using the formula:

$pH = - log [H_{3}O^{+}]$

Given the pH of solution is 3.2.

Finding out the concentration of hydronium ion from pH.

$pH = - log[H_{3}O^{+}]$

$3.2 = - log [H_{3}O^{+}]$

$[H_{3}O^{+}] = 10^{-3.2}$

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Therefore, the hydronium ion concetration of the solution is $6.3 * 10^{-4} M$

3 0

3 years ago

Suppose that a 10-mL sample of a solution is to be tested for I− ion by addition of 1 drop (0.2 mL) of 0.13 M Pb(NO3)2.

Liono4ka [1.6K]

The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

Given data :

Volume of solution to be tested for I-ion = 10 mL

Volume of Pb(NO₃)₂ = 0.2 mL

molarity of Pb(NO₃)₂ = 0.13 M

<h3>Determine the number of I that must be present </h3>

First step : calculate conc of PB²⁺ ions in the solution

conc of PB²⁺ ions = ( molarity of Pb(NO₃)₂ * volume of Pb(NO₃)₂ ) / ( total volume )

= ( 0.13 * 0.2 ) / ( 10 + 0.2 )

= ( 0.026 ) / ( 10.2 ) = 0.002549 M

Next step : determine the molarity of I

using the dissociation reaction of PbI₂

PbI₂(s) ---> Pb²⁺ (aq) + 2I (aq)

also; Ksp = [ Pb²⁺ ] [ I ]² ---- ( 1 )

From the question the given value of Ksp = 8.49 * 10⁻⁹

Therefore equation ( 1 ) becomes

8.49 * 10⁻⁹ = ( 0.002549 ) * [ I ]²

[ I ] = √ ( 8.49 * 10⁻⁹ ) / ( 0.002549 )

= 0.0018 M

Final step : Determine the minimum number of grams of I

moles of I = molarity of I * total volume

= 0.0018 M * 10.2 mL

= 0.01836 * 10⁻³ mol

Hence we can conclude that The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol

Learn more about Pb(NO₃)₂ : brainly.com/question/25071409

8 0

2 years ago

A student obtains a beaker containing a solution that is determined to have a hydrogen ion

OleMash [197]

Answer:

pH = 13.1

Basic

Explanation:

Step 1: Given data

Hydrogen ion concentration ([H⁺]): 6.7 × 10⁻¹⁴ M

Step 2: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺]

pH = -log 6.7 × 10⁻¹⁴ = 13.1

When pH < 7, the solution is acid.
When pH = 7, the solution is neutral.
When pH > 7, the solution is basic.

Since pH > 7, the solution is basic.

6 0

2 years ago