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dangina [55]
3 years ago
14

If a solution has a pOH of 8.71, what is the [H+]?

Chemistry
1 answer:
TEA [102]3 years ago
6 0

Answer: 5.1\times 10^{-6}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH+pOH=14

Putting in the values:

pH=14-8.71=5.29

5.29=-log[H^+]

[H^+]=5.1\times 10^{-6}

Thus [H^+] is 5.1\times 10^{-6}M

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It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen
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Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}

To calculate the value of k which is a dependent variable for the above equation ; we have:

k = \dfrac{-In(1-0.40)}{200^{2.5}}

k = 9.030 \times 10 ^{-7}

The time needed for 50% transformation can be determined as follows:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}

t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}

= 200.00183 min

The rate of reaction for Avrami equation is:

rate = \dfrac{1}{t_{0.5}}

rate = \dfrac{1}{200.00183}

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

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