There are 5.66 moles of hydrogen in the sample of talc(hydrated magnesium silicate).
Given,
Talc formula is 
moles of magnesium = 8.5 moles
The stoichiometry of magnesium and hydrogen is 3 : 2,
So 3 moles of magnesium is equivalent to 2 moles of hydrogen.
Then 8.5 moles of magnesium is equivalent to 
=5.6666 moles
<h3>Talc </h3>
Talc(hydrated magnesium silicate), often known as talcum, is a type of clay mineral made up of hydrated magnesium silicate, having the formula Mg3Si4O10(OH)2. Baby powder is made of powdered talc, frequently mixed with corn starch. This mineral serves as a lubricant and thickening agent. It serves as a component in paint, pottery, and roofing materials. It serves as a key component in many cosmetics. It can be found as foliated to fibrous aggregates and in a remarkably uncommon crystal form. It is foliated with a two-dimensional platy form, has a flawless basal cleavage, and an irregular flat fracture.
Talc(hydrated magnesium silicate), the softest mineral, is assigned a value of 1 on the Mohs scale of mineral hardness, which is based on scratch hardness comparisons.
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Answer:
202 g/mol
Explanation:
Let's consider the neutralization between a generic monoprotic acid and KOH.
HA + KOH → KA + H₂O
The moles of KOH that reacted are:
0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol
The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.
1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:
0.2688 g/1.33 × 10⁻³ mol = 202 g/mol
AB+XY->AY+XB
We know that the answer would be KCl because of the switching that takes place during a double displacement reaction. Just like Zn and MnO4 switched and combined, the remaining elements, K and Cl, will combine.
We know that the answer is simply KCl because both K and Cl have an ion of only +/-1, meaning when they cross, no suffixes are made, since their ions are only 1.
For example, if you combined Mg with Cl, you would get MgCl2, because Mg has an ion of +2.
I hope this helps!
Explanation:
Starting moles of ethanol acid = 0.020 mol
At the equilibrium 50 % of the ethanol acid molecules reacted
∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %
= 0.010 mol
Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol
Moles of the product 
gas formed are calculated as
0.010 mol CH3COOH * 1 mol / 2 mol CH3COOH
= 0.005 mol
Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol
That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol
Now Calculate the pressure :
0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas
P1/n1 = P2/n2
P2 = P1*n2 / n1
= 0.74 atm * 0.015 mol / 0.020 mol
= 0.555 atm
Answer: A balanced equation for the given reaction is 
.
Explanation:
The reaction equation will be as follows.
Number of atoms on the reactant side is as follows.
Number of atoms on the product side is as follows.
Since number of atoms on both the reactant and product sides are equal. Hence, the reaction equation is balanced.
Thus, we can conclude that a balanced equation for the given reaction is .
