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3 years ago

How do you convert 16.7 inches to feet?

Chemistry

2 answers:

vovangra [49]3 years ago

8 0

the answer is 1.39 feet

beks73 [17]3 years ago

6 0

There are 12 inches in a foot.

16.7 in ÷ 12 in = 1.39 ft

Or if you prefer to the nearest tenth:

1.4 ft.

Good luck! :)

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Diamond is a natural form of pure carbon. What number of atoms of carbon are in a 1.00-carat diamond (1.00 carat = 0.200 g)?

slega [8]

Answer:

1.004×10²²

Explanation:

The molar mass of carbon is 12 g/mol

which means that:

1 mole of carbon atoms has a mass of 12 grams.

Since, diamond is a allotrope of carbon.

Mass of 1.00-carat diamond in grams is:

1.00 carat = 0.200 g

Since, 1 mole of C contains 6.022×10²³ atoms of C

So,

12 grams contains 6.022×10²³ atoms of C

1 gram contains 6.022×10²³/ 12 atoms of C

0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C

Thus,

1 carat diamond contains 1.004×10²² atoms of C.

8 0

3 years ago

18 An important environmental consideration is the appropriate disposal of cleaning solvents. An environmental waste treatment c

Katyanochek1 [597]

Answer:

a) Percentage by mass of carbon: 18.3%

Percentage by mass of hydrogen: 0.77%

b) Percentage by mass of chlorine: 80.37%

c) Molecular formula: $C_{2} H Cl_{3}$

Explanation:

Firstly, the mass of carbon must be determined by using a conversion factor:

$0.872g CO _{2} *\frac{12g C}{44g CO_{2} } = 0.238g CO_{2}$

The same process is used to calculate the amount of hydrogen:

$0.089g H_{2}O*\frac{2g H}{18g H_{2}O } = 0.010g H$

The percentage by mass of carbon and hydrogen are calculated as follows:

%C $\frac{0.238g}{1.3g} *100%$ = 18.3%

%H $\frac{0.010g}{1.3g} *100%$ =0.77%

From the precipation data it is possible obtain the amount of chlorine present in the compound:

$1.75 AgCl*\frac{35.45g Cl}{143.45g AgCl}$ = 0.43g AgCl

Let's calculate the percentage by mass of chlorine:

%Cl= $\frac{0.43g}{0.535g} * 100%$ = 80.37%

Assuming that we have 100g of the compound, it is possible to determine the number of moles of each element in the compound:

$18.3g C*\frac{1mol C}{12g C} = 1.52mol C$

$0.77g H*\frac{1mol H}{1g H} = 0.77mol H$

$80.37gCl*\frac{1molCl}{35.45g Cl} = 2.27mol Cl$

Dividing each of the quantities above by the smallest (0.77mol), the subscripts in a tentative formula would be

$C=\frac{1.52}{0.77} = 1.97$ ≈ 2

$H = \frac{0.77}{0.77} = 1$

$Cl =\frac{2.27}{0.77}=2.94$ ≈3

The empirical formula for the compound is:

$C_{2} H Cl_{3}$

The mass of this empirical formula is:

mass of C + mass of H + mass of Cl= 24g +1+ 106.35 =131.35g

This mass matches with the molar mass, which means that the supscript in the molecular formula are the same of the empirical one.

5 0

3 years ago

HELP ASAP GIVING BRIANALST TO THE FRIST TO ANSWER

Kisachek [45]

Answer:

yes the ones u chose are correct.

Explanation:

8 0

3 years ago

How do you calculate mass using density and volume?

skad [1K]

Example:

Mass = ?

Density = 25 g/mL

Volume = 5 mL

therefore:

d = m / V

25 = m / 5

m = 25 x 5

m = 125 g

hope this helps!

7 0

3 years ago

Thermochemical equations are chemical equations that include the __________ of the reaction.

irga5000 [103]

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH. In variable form, a thermochemical equation would look like this:

A + B → CΔH = (±) #

Where {A, B, C} are the usual agents of a chemical equation with coefficients and “(±) #” is a positive or negative numerical value, usually with units of kJ.

please mark as brainliest

5 0

3 years ago