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3 years ago

How do you convert 16.7 inches to feet?

Chemistry

2 answers:

vovangra [49]3 years ago

8 0

the answer is 1.39 feet

beks73 [17]3 years ago

6 0

There are 12 inches in a foot.

16.7 in ÷ 12 in = 1.39 ft

Or if you prefer to the nearest tenth:

1.4 ft.

Good luck! :)

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Atoms of which of the following elements have the smallest atomic radius?

Ad libitum [116K]

Answer:

The answer is helium, I hope this is helpful :)

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3 years ago

Four nails have a total mass of 4.42 grams how many moles of iron atoms do they contain

deff fn [24]

Answer:4.42 g= 1 mol/55.845 =.079 moles of Fe

Explanation:Given 4.42 grams of Fe. The atomic weight of Fe(iron) found on the periodic table is 55.845. Divide grams by the atomic weight to convert to moles.

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4 years ago

Determine the volume (in liters) of a 87.8-9 sample of OF2 gas at 307 torr and 264°C.

expeople1 [14]

Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

$PV=nRT\\\\PV=\frac{m}{MM}RT$

Thus, by solving for volume we obtain:

$V=\frac{mRT}{MM*P}$

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

$V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L$

Best regards!

6 0

3 years ago

Calculate the solubility of CaF2 in g/L (Ksp = 4.0 x 10-8). 2. What is the pH of a solution containing a hydrogen ion concentrat

Pepsi [2]

Answer:

$\large \boxed{1. \text{ 0.17 g/L; 2. 3.52; 3. Cl; 4. (a) +3; (b) +4; (c) +6}}$

Explanation:

1. Solubility of CaF_2

(a) Molar solubility

CaF₂ ⇌ Ca²⁺ + 2F⁻

$K_{\text{sp }} = \text{[Ca$^{2+}$]}\text{[F$^{-}$]}^{2}= 4.0 \times 10^{-8}\\s(2s)^{2}=4.0 \times 10^{-8}\\4s^{3} = 4.0 \times 10^{-8}\\s^{3} = 1.0 \times 10^{-8}\\s =2.2 \times 10^{-3}\text{ mol/L}$

(b) Mass solubility

$\text{Solubility} = 2.2 \times 10^{-3} \text{ mol/L} \times \dfrac{\text{78.07 g}}{\text{1 L }} = \text{0.17 g/L}\\\\\text{The solubility of CaF$_{2}$ is $\large \boxed{\textbf{0.17 g/L}}$}$

2. pH

pH = -log [H⁺] = -log(3.0 × 10⁻⁴) = 3.52

3. Oxidizing and reducing agents

Zn + Cl₂ ⟶ ZnCl₂

$\rm \stackrel{\hbox{0}}{\hbox{Zn}} + \stackrel{\hbox{0}}{\hbox{ Cl}_{2} }\longrightarrow \stackrel{\hbox{+2}}{\hbox{Zn}}\stackrel{\hbox{-1}}{\hbox{Cl}_{2}}$