Answer:
The solution in beaker A is unsaturated
The solution in beaker B is saturated
Explanation:
A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. An unsaturated solution is a solution that contains less solute than it can normally hold at a particular temperature.
If more solute is added to a saturated solution, the added solute does not dissolve completely. However, if more solute is added to an unsaturated solution, the added solute dissolves.
Answer: 69.72 kg of cryolite will be produced.
Explanation:
The balanced chemical equation is:
To calculate the moles, we use the equation:
moles of 
= 
moles of 
= 
moles of 
= 
As 1 mole of reacts with 6 moles of
166 moles of reacts with = 
moles of
As 1 mole of reacts with 12 moles of
166 moles of reacts with = 
moles of
Thus is the limiting reagent.
As 1 mole of produces = 2 moles of cryolite
166 moles of reacts with = 
moles of cryolite
Mass of cryolite 
= 
Thus 69.72 kg of cryolite will be produced.
<h3>
Answer:</h3>
Lead-205 (Pb-205)
<h3>
Explanation:</h3>
<u>We are given;</u>
We are supposed to identify its product after an alpha decay;
- Polonium-209 has a mass number of 209 and an atomic number of 84.
- When an element undergoes an alpha decay, the mass number decreases by 4 while the atomic number decreases by 2.
- Therefore, when Po-209 undergoes alpha decay it results to the formation of a product with a mass number of 205 and atomic number of 82.
- The product from this decay is Pb-205, because Pb-205 has a mass number of 205 and atomic number 82.
- The equation for the decay is;
²⁰⁹₈₄Po → ²⁰⁵₈₂Pb + ⁴₂He
- Note; An alpha particle is represented by a helium nucleus, ⁴₂He.
Answer:
%H = 6.72 %
Explanation:
Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.
So,
Percent composition of Hydrogen will be given as,
%H = Total mass of H / Molecular Mass of Acetic Acid × 100
So,
Total Mass of H = 1.01 × 4 = 4.04 g
Molecular Mass of Acetic acid = 60.052 g/mol
Putting values in above formula,
%H = 4.04 g/mol ÷ 60.052 g/mol × 100
%H = 6.72 %
