Answer:
Explanation:
efficiency = (energy output / energy input)
energy input = ivt where i is current = 6 A, v is volts = 140 and t time = 11 seconds
energy input = 6 × 140 × 11 = 9240 J
energy output = 0.64 × 9240 = 5913.6 J
510 pound-force = 2268.593 N
at height h, potential energy = mgh = 5913.6 J
2268.593 × h = 5913.6
h = 5913.6 / ( 2268.593) = 2.61 m
Answer:
Solar
Explanation:
The Hubble space telescope is a bus-sized satellite powered by huge solar panels.
Answer:The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.
Explanation:
The most common injuries were sprains/strains (39% of the total), lacerations (22%), and contusions (15%). Forty-nine percent of the injuries resulted in one or more lost or restricted workdays; 25% resulted in 7 or more lost or restricted workdays.
Answer:
Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb
Vg = specific volume of saturated steam = 0.430129 ft^3/lb
Explanation:
Given data:
water temperature is given as 287-degree Celcius
we have to find Vf and Vg
Vf = specific volume of saturated liquid
Vg = specific volume of saturated steam
we know that from the saturated steam table we can find these value
therefore for temperature 287-degree Celcius
Vf = specific volume of saturated liquid = 0.0217158 ft^3/lb
Vg = specific volume of saturated steam = 0.430129 ft^3/lb
Answer:
At the point when the quantity of bit strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just part strings to processors and not client level strings to processors. At the point when the quantity of part strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used all the while. Be that as it may, when a part string obstructs inside the portion (because of a page flaw or while summoning framework calls), the comparing processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, in this way expanding the use of the multiprocessor system.When the quantity of part strings is not exactly the quantity of processors, at that point a portion of the processors would stay inert since the scheduler maps just bit strings to processors and not client level strings to processors. At the point when the quantity of bit strings is actually equivalent to the quantity of processors, at that point it is conceivable that the entirety of the processors may be used at the same time. Be that as it may, when a part string hinders inside the piece (because of a page flaw or while summoning framework calls), the relating processor would stay inert. When there are more portion strings than processors, a blocked piece string could be swapped out for another bit string that is prepared to execute, along these lines expanding the usage of the multiprocessor framework.
