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Sophie [7]
2 years ago
12

How many grams of KBr is required to prepare 100 mL of 2.0 M KBr solution?

Chemistry
1 answer:
sesenic [268]2 years ago
4 0

Answer:

23.8g

Explanation :

Convert 2.0M into mol using mol= concentration x volume

2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)

= 0.2 mol

We can now find grams by using the molar mass of KBr

=119.023 g/mol (Found online) webqc.org

but can be be calculated by using the molecular weight of K and Br found on the periodic table

We can now calculate the grams by using grams=mol x molar mass

119.023g/mol x 0.2mol

= 23.8046 g

=23.8g (rounded to 1decimal place)

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Match the following associations. Exothermic or endothermic
Alekssandra [29.7K]

<u>Answer:</u>

<em>1) ∆H is positive \Rightarrow Endothermic </em>

<em>2) E_p>E_r \Rightarrow Endothermic  </em>

<em>3) Energy is absorbed \Rightarrow Endothermic </em>

<em>4) E_r>E_p \Rightarrow Exothermic </em>

<em>5) ∆H is negtive \Rightarrow Exothermic </em>

<em></em>

<u>Explanation:</u>

∆H is called as enthalpy change  

It is also called as Heat of reaction

Energy is required for the bond to break a bond.

Energy is released when a bond is formed.

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that is

H-H+Cl-Cl>2H-Cl

We see in this equation, bonds between hydrogen and chlorine molecules gets broken and on the right side bond is formed in HCl.

If energy of products greater than energy of reactants then the reaction enthalpy change is endothermic .

If energy of products lesser than energy of reactants then the reaction enthalpy change is exothermic .

For example  

\Delta H=E_p-E_r

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8 0
3 years ago
1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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