Given :
Force,
.
Force is acting at point A( 2 m, 3 m ) and B( 3 m, 5 m )
To Find :
The work done by force F .
Solution :
Displacement vector between point A and B is :

Now, we know work done is given by :

W = 12000 J
Therefore, work done by force is 12000 J .
Answer:
An architect will help you determine exactly what you need and come up with inventive ideas to solve even the most complex design problems. Think of us as professional 3D problem solvers! An architect can and should lift your project out of the ordinary.
Explanation:
What are the 3 main functions of an architect?
Design: Architects must design, plan, and develop concepts to create construction plans and technical documents. These are based on client requirements and ideas. Research: Architects must learn about the different building codes, safety regulations, construction innovations and city laws that affect their designs
What are the 7 types of architecture?
There are several main types of architects who focus on different types of structures and designs.
...
Commercial Architects
Office buildings / skyscrapers.
Hotels.
Bridges.
Schools.
Museums.
Government buildings.
Multi-unit residential buildings.
Pretty much any type of building that's not a residential home.
Answer:
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Explanation:
Answer:
<em>D. Determine saving or debt</em>
Explanation:
Answer:
The change in entropy is found to be 0.85244 KJ/k
Explanation:
In order to solve this question, we first need to find the ration of temperature for both state 1 and state 2. For that, we can use Charles' law. Because the volume of the tank is constant.
P1/T1 = P2/T2
T2/T1 = P2/P1
T2/T1 = 180 KPa/120KPa
T2/T1 = 1.5
Now, the change in entropy is given as:
ΔS = m(s2 - s1)
where,
s2 = Cv ln(T2/T1)
s1 = R ln(V2/V1)
ΔS = change in entropy
m = mass of CO2 = 3.2 kg
Therefore,
ΔS = m[Cv ln(T2/T1) - R ln(V2/V1)]
Since, V1 = V2, therefore,
ΔS = mCv ln(T2/T1)
Cv at 300 k for carbondioxide is 0.657 KJ/Kg.K
Therefore,
ΔS = (3.2 kg)(0.657 KJ/kg.k) ln(1.5)
<u>ΔS = 0.85244 KJ/k</u>