The maximum Speed of the Sprinter from the velocity time graph of his motion is; 11.98 m/s
<h3>How to find the maximum speed?</h3>
We are given;
Initial Speed; u = 2.5 s
Total distance; d = 100 m
Total time; T = 9.6 s
The total distance is;
d = ¹/₂(9.6 + (9.6 - 2.5) * v
where v is maximum speed.
Thus;
¹/₂(9.6 + (9.6 - 2.5) * v = 100
16.7v = 200
v = 200/16.7
v = 11.98 m/s
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Answer:
View Image
Explanation:
You didn't provide me a picture of the opamp.
I'm gonna assume that this is an ideal opamp, therefore the input impedance can be assumed to be ∞ . This basically implies that...
- no current will go in the inverting(-) and noninverting(+) side of the opamp
- V₊ = V₋ , so whatever voltage is at the noninverting side will also be the voltage at the inverting side
Since no current is going into the + and - side of the opamp, then
i₁ = i₂
Since V₊ is connected to ground (0V) then V₋ must also be 0V.
V₊ = V₋ = 0
Use whatever method you want to solve for v_out and v_in then divide them. There's so many different ways of solving this circuit.
You didn't give me what the input voltage was so I can't give you the entire answer. I'll just give you the equations needed to plug in your values to get your answers.
Answer:
The grip
Explanation:
the head of all headed bolt (except countersunk head bolt)
Answer:
Check the explanation
Explanation:
The loop invariant has to satisfy some amount of requirements to be of good use. Another complex factor as to why a loop is the question of loop termination. A loop that doesn’t terminate can’t invariably be correct, and in fact the computation in whatever form amounts to nothing. The total axiomatic description of a while construct will have to involve all of the following to be true, in which I is the loop invariant:
P => I
{I and B} S {I}
(I and (not B)) => Q
Then the loop terminates
