Answer:
Creating vacancies in ceramics. Consider doping ZrO₂ with small concentrations of Nb205. The valence of Nb is 5. Assume that Nb ions sit in Zr ion sites
a. A substitutional defect will be produced.
b. With this dopping, the Nb increases electron band conduction and decreases oxygen anion conduction in ZrO₂.
Explanation:
(a) The defect produced by dopping a little concentration of Nb₂O5 with Nb in the +5 charge state is known as a substitutional defect.
(b) With this dopping, the Nb increases electron band conduction and decreases oxygen anion conduction in ZrO₂.
Moreover, if oxygen vacancies are rate-limiting defect, the corrosion of ZrO₂ decreases and if electrons are rate-limiting then the corrosion of ZrO₂ is accelerated.
Answer: The United States must lead the space race to prevent future wars.
Explanation: Hope this helps
Answer:
Load sup[port by beam is 1040 lb/ft
Explanation:
Given data:
dead load of floor is 50 psf
live load of floor is 80 psf
load per meter can be determined as
Load/mt length = load intensity × effective width
total load = deal load + live load
= 50 + 80 = 130 psf
load /mt length = 130 × 8
= 1040 p/ft = 1.04 k /ft
hence load sup[port by beam is 1040 lb/ft
Answer:
The energy, that is dissipated in the resistor during this time interval is 153.6 mJ
Explanation:
Given;
number of turns, N = 179
radius of the circular coil, r = 3.95 cm = 0.0395 m
resistance, R = 10.1 Ω
time, t = 0.163 s
magnetic field strength, B = 0.573 T
Induced emf is given as;
where;
ΔФ is change in magnetic flux
ΔФ = BA = B x πr²
ΔФ = 0.573 x π(0.0395)² = 0.002809 T.m²
According to ohm's law;
V = IR
I = V / R
I = 3.0848 / 10.1
I = 0.3054 A
Energy = I²Rt
Energy = (0.3054)² x 10.1 x 0.163
Energy = 0.1536 J
Energy = 153.6 mJ
Therefore, the energy, that is dissipated in the resistor during this time interval is 153.6 mJ
