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alexgriva [62]
3 years ago
8

Julissa combined baking soda and calcium chloride solution in a beaker. she observed bubbling and a white solid formed. Julissa

completed the reaction again after warming the solutions. What changes will julissa most likely see in the warmer reaction.?
A) The bubbling and white solid formation would occur faster
B)The bubbles and white solid formation would happen slower
C) The bubbling or white solid formation would not be created at all
D) Only the bubbling would occur, but no white solid particles would from.
(50 points pls help)
Chemistry
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

A

Explanation:

With chemical reactions, there are various factors that affect the rate of the reaction. One of these is temperature.

When you raise the temperature, the reaction will move faster. Why? Temperature is directly correlated with the kinetic energy (basically, the energy that makes the particles move). Higher temperatures mean higher kinetic energies. Particles with higher kinetic energies move faster, which makes them more likely to collide. When collisions occur more frequently, the reaction follows through more quickly.

Thus, when Julissa warms the solutions, she will see that bubbling and white solid formation (the products of the reaction) occus faster. So, the answer is A.

Hope this helps!

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<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

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Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

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P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

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