Answer:
6.25 X10^{-9} = Ka

Explanation:
The ionic equation for the hydrolysis of the cation of the given salt will be:

The expression for Ka will be:
Ka = ![\frac{[H^{+}][MOH]}{[M^{+}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BMOH%5D%7D%7B%5BM%5E%7B%2B%7D%5D%7D)
As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH
pH = -log [H⁺]
[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]
Let us calculate Ka from this,
Ka = 
The relation between Ka an Kb is
KaXKb =10⁻¹⁴

Answer:
a) 24.31 g
b) 16.69 g
Explanation:
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.
After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.
Therefore, Pressure of Kr = 0.193 atm
Pressure of CO2 = 0.729 - 0.193 = 0.536 atm
Their mole fraction can be also determined as follows:
CO2 = 
CO2 = 
= 0.735
Also; for Kr ; we have
Kr =
Kr = 0.265
Molar mass of CO2 = 44 g/mol
Molar mass of Kr = 83.78 g/mol
Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34
Mass of Kr = 0.265 * 83.78 = 22.20
Total mass = 32.34 +22.20 = 54.54
The Percentage of gas in mixture is as follows:
% CO2 =
* 100 %
= 0.5930
= 59.30%
(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g
% Kr =
* 100 %
= 0.407
= 40.70 %
(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g
Answer:
because I don't know the answers sorry maam