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alexgriva [62]
3 years ago
8

Julissa combined baking soda and calcium chloride solution in a beaker. she observed bubbling and a white solid formed. Julissa

completed the reaction again after warming the solutions. What changes will julissa most likely see in the warmer reaction.?
A) The bubbling and white solid formation would occur faster
B)The bubbles and white solid formation would happen slower
C) The bubbling or white solid formation would not be created at all
D) Only the bubbling would occur, but no white solid particles would from.
(50 points pls help)
Chemistry
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

A

Explanation:

With chemical reactions, there are various factors that affect the rate of the reaction. One of these is temperature.

When you raise the temperature, the reaction will move faster. Why? Temperature is directly correlated with the kinetic energy (basically, the energy that makes the particles move). Higher temperatures mean higher kinetic energies. Particles with higher kinetic energies move faster, which makes them more likely to collide. When collisions occur more frequently, the reaction follows through more quickly.

Thus, when Julissa warms the solutions, she will see that bubbling and white solid formation (the products of the reaction) occus faster. So, the answer is A.

Hope this helps!

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What is the noble gas electron configuration of aluminum (Al)? A. [Ne] 3s2 3p1 B. [Ne] 2s2 2p1 C. [Ar] 3s2 3p1 D. [Ar] 1s2 2s2 2
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Read 2 more answers
When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed
gizmo_the_mogwai [7]

Answer:

             66 g of CO₂

Solution:

The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
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