Answer:
The Kₐ of the weak acid is 1.033×10⁻⁴
Explanation:
The dissociation of a weak acid in aqueous solution is limited to about 5 to 10%
The acid dissociation reaction is given as follows;
HA (aq) + H₂O (l) → H₃O⁺(aq) + A⁻ (aq)
Given that the pH = 2.5, we have
pH = -log₁₀[H₃O⁺] = 2.5
∴ [H₃O⁺] = 10^(-2.5) = 0.0031623
Kₐ = [H₃O⁺][A⁻]/[HA] = (0.0031623^2)/(0.1 - 0.0031623) = 1.033×10⁻⁴
The acid dissociation constant, Kₐ for weak acid is very low as obtained
Answer:
The answer is
<h3>6000 N/m² or 6000 Pa</h3>Explanation:
The pressure exerted by an object given the force of the object and the area can be found by using the formula
where
P is the pressure
f is the force
a is the area
From the question
f = 2400 N
a = 0.4 m²
So we have
We have the final answer as
<h3>6000 N/m² or 6000 Pa</h3>Hope this helps you
Answer: 642.93 g of NaCl
Explanation:
11.00 mol NaCl x __58.448 g__ = 642.928 g of NaCl
1 mol NaCl
I would round to 642.93 g of NaCl, but round to however many significant figures asked for.
My chemistry teacher made this map (image attached) to teach us how to do conversions. Just follow the map. I think it's pretty straight forward. I hope this helps.
