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boyakko [2]
3 years ago
10

As water molecules move through the hydrological cycle, water both gains and loses energy. In which case would the water be losi

ng energy?
Chemistry
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

In condensation water loses energy in water cycle.

Explanation:

The water cycle describes the continuous motion of water on, above, and below the surface of earth and it is also known as hydrologic cycle. In this process water both gains and loses energy. When evaporation occurs it gains energy from surrounding and cools the environment. When condenses occurs it loses energy and warms the environment.

Triss [41]3 years ago
5 0
Condensation. I just completed the test
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How many moles of solid NaF would have to be added to 1.0 L of 0.115 M HF solution to achieve a buffer of pH 3.46? Assume there
astra-53 [7]

Answer : The  moles of solid NaF is, 1.09 mole.

Explanation : Given,

pH = 3.46

K_a=7.2\times 10^{-4}

Concentration of HF = 0.115 M

Volume of solution = 1.0 L

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (7.2\times 10^{-4})

pK_a=4-\log (7.2)

pK_a=3.14

Now we have to calculate the moles of HF.

\text{Moles of }HF=\text{Concentration of }HF\times \text{Volume of solution}

\text{Moles of }HF=0.115M\times 1.0L=0.115mol

Now we have to calculate the moles of NaF.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{\text{Moles of NaF}}{\text{Moles of HF}}

Now put all the given values in this expression, we get:

3.46=3.14+\log (\frac{\text{Moles of NaF}}{0.115})

\text{Moles of NaF}=1.09mol

Thus, the moles of solid NaF is, 1.09 mole.

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Answer:

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